Evaluate The Following: 1.C 4,4 2. C7,3+C11,9 3. C - Gauthmath

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Answer(a) \(0.65 \text{ m/s}\) (b) \(60 \text{ m/s}\) (c) \(5.16 \times 10^{6} \text{ m/s}\)ExplanationStep 1: Convert \( 65 \text{ cm/s} \) to \( m/s \) by recognizing that \( 1 \text{ cm} = 0.01 \text{ m} \). Therefore, \( 65 \text{ cm/s} = 0.65 \text{ m/s} \). Step 2: Convert \( 1000 \text{ cm/min} \) to \( m/s \) by first converting \( \text{cm/min} \) to \( \text{m/min} \) and then to \( \text{m/s} \). Since \( 1 \text{ cm} = 0.01 \text{ m} \), \( 1000 \text{ cm/min} = 10 \text{ m/min} \). Then, since there are \( 60 \text{ seconds} \) in \( 1 \text{ minute} \), \( 10 \text{ m/min} = 10 \text{ m} \times \frac{1}{60} \text{ per second} = 0.1667 \text{ m/s} \). Step 3: Convert \( 86 \text{ km/min} \) to \( m/s \) by first converting \( \text{km/min} \) to \( \text{m/min} \) and then to \( \text{m/s} \). Since \( 1 \text{ km} = 1000 \text{ m} \), \( 86 \text{ km/min} = 86000 \text{ m/min} \). Then, since there are \( 60 \text{ seconds} \) in \( 1 \text{ minute} \), \( 86000 \text{ m/min} = 86000 \text{ m} \times \frac{1}{60} \text{ per second} = 1433.33 \text{ m/s} \). So, the answers are: (a) \( 0.65 \text{ m/s} \) (b) \( 60 \text{ m/s} \) (c) \( 5.16 \times 10^{6} \text{ m/s} \).Click to rate:70.4(228 votes)Search questionBy textBy image/screenshotDrop your file here orClick Hereto upload