F(x)=2x+3, G(x)=-x^2+5, (f \circ G)(x) - Symbolab

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x^2	x^{\msquare}	\log_{\msquare}	\sqrt{\square}	\nthroot[\msquare]{\square}	\le	\ge	\frac{\msquare}{\msquare}	\cdot	\div	x^{\circ}	\pi
\left(\square\right)^{'}	\frac{d}{dx}	\frac{\partial}{\partial x}	\int	\int_{\msquare}^{\msquare}	\lim	\sum	\infty	\theta	(f\:\circ\:g)	f(x)

▭\:\longdivision{▭}

\times \twostack{▭}{▭}

+ \twostack{▭}{▭}

- \twostack{▭}{▭}

\left(

\right)

\times

\square\frac{\square}{\square}

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x^2	x^{\msquare}	\log_{\msquare}	\sqrt{\square}	\nthroot[\msquare]{\square}	\le	\ge	\frac{\msquare}{\msquare}	\cdot	\div	x^{\circ}	\pi
\left(\square\right)^{'}	\frac{d}{dx}	\frac{\partial}{\partial x}	\int	\int_{\msquare}^{\msquare}	\lim	\sum	\infty	\theta	(f\:\circ\:g)	f(x)

- \twostack{▭}{▭}	\lt	7	8	9	\div	AC
+ \twostack{▭}{▭}	\gt	4	5	6	\times	\square\frac{\square}{\square}
\times \twostack{▭}{▭}	\left(	1	2	3	-	x
▭\:\longdivision{▭}	\right)	.	0	=	+	y

\mathrm{simplify} \mathrm{solve\:for} \mathrm{inverse} \mathrm{tangent} \mathrm{line} See All area asymptotes critical points derivative domain eigenvalues eigenvectors expand extreme points factor implicit derivative inflection points intercepts inverse laplace inverse laplace partial fractions range slope simplify solve for tangent taylor vertex geometric test alternating test telescoping test pseries test root test Go Steps Graph Related Examples Generated by AI AI explanations are generated using OpenAI technology. AI generated content may present inaccurate or offensive content that does not represent Symbolab's view. Verify your Answer Subscribe to verify your answer Subscribe Save to Notebook! Sign in to save notes Sign in Verify Save Show Steps Hide Steps

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f(x)=2x+3, g(x)=-x^2+5, (f \circ g)(x)

F(x)=2x+3, G(x)=-x^2+5, (f \circ G)(x) - Symbolab

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F(x)=2x+3, G(x)=-x^2+5, F-g - Symbolab

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