F(x) = X^3 + 4x^2 – 3x + 10, G(x) = X + 4 - Sarthaks EConnect

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f(x) = x^3 + 4x^2 – 3x + 10, g(x) = x + 4 ← Prev Question Next Question → 0 votes 43.3k views

asked Feb 12, 2020 in Polynomials by ShasiRaj (56.4k points)

Using the remainder theorem, find the remainder when f(x) is divided by g(x) and verify the by actual division :

f(x) = x3 + 4x2 – 3x + 10, g(x) = x + 4

factorization of polynomials
class-9

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commented Oct 4, 2021 by Jeetesh Kumar (10 points) Ekdam sahi answer

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1 Answer

+1 vote

answered Feb 12, 2020 by Tahseen Ahmad (30.6k points) selected Feb 12, 2020 by ShasiRaj Best answer

f(x) = x3 + 4x2 – 3x + 10, g(x) = x + 4

Put g(x) = 0

⇒ x + 4 = 0 or x = -4

Remainder = f(-4)

Now,

f(-4) = (-4)3 + 4(-4)2 – 3(-4) + 10

= -64 + 64 + 12 + 10

= 22

Actual Division:

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F(x) = X^3 + 4x^2 – 3x + 10, G(x) = X + 4 - Sarthaks EConnect

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