Find The Absolute Extrema Of The Function G(x) = X/ln(x) On The Interval ...
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Best Newest Oldest By: Best Newest Oldesttake the derivative of x/ln and set =0
(x/lnx)' = (lnx -x(1/x)/ln^2(x) = 0
solve for x
(lnx -1)/ln^2x =0
lnx -1 =0
lnx =1
x = about 2.7818
check g(2.7818) and g(2) and g(9), the endpoints
g(2) = 2/ln2 = about 2.89
g(9) = 9/ln9 = about 4.1
g(2.8) = 2.8/ln2.8 =2.7
2.7 is the local and global minimum on the interval 2 to 9
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