Find The Set Of Values For X For Which X^2 - 9x <= 36 - MyTutor

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Rearrange to get x^2 - 9x - 36 <= 0 Solve quadratic (x-12)(x+3) <= 0 Solve for x x = 12, x = -3

Now, we have key points 12 and -3, we need the range of values for x where x^2 - 9x - 36 <= 0.

So, we can visualise quadratic. It's positive, so the range of values lower than y=0 will be -3 < x < 12. This is the answer.

DDAnswered by Daniel D. • Maths tutor

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