Finding The Roots Of Polynomials - Tiger Algebra
Step 1 :
Equation at the end of step 1 :
((((9•(x4))-(9•(x3)))-(2•29x2))+4x)+24Step 2 :
Equation at the end of step 2 :
((((9•(x4))-32x3)-(2•29x2))+4x)+24Step 3 :
Equation at the end of step 3 :
(((32x4 - 32x3) - (2•29x2)) + 4x) + 24Step 4 :
Polynomial Roots Calculator :
4.1 Find roots (zeroes) of : F(x) = 9x4-9x3-58x2+4x+24Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading CoefficientIn this case, the Leading Coefficient is 9 and the Trailing Constant is 24. The factor(s) are: of the Leading Coefficient : 1,3 ,9 of the Trailing Constant : 1 ,2 ,3 ,4 ,6 ,8 ,12 ,24 Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | -20.00 | |
| -1 | 3 | -0.33 | 16.67 | |
| -1 | 9 | -0.11 | 22.85 | |
| -2 | 1 | -2.00 | 0.00 | x+2 |
| -2 | 3 | -0.67 | 0.00 | 3x+2 |
| -2 | 9 | -0.22 | 20.37 | |
| -3 | 1 | -3.00 | 462.00 | |
| -4 | 1 | -4.00 | 1960.00 | |
| -4 | 3 | -1.33 | -34.67 | |
| -4 | 9 | -0.44 | 11.91 | |
| -6 | 1 | -6.00 | 11520.00 | |
| -8 | 1 | -8.00 | 37752.00 | |
| -8 | 3 | -2.67 | 226.67 | |
| -8 | 9 | -0.89 | -13.44 | |
| -12 | 1 | -12.00 | 193800.00 | |
| -24 | 1 | -24.00 | 3076920.00 | |
| 1 | 1 | 1.00 | -30.00 | |
| 1 | 3 | 0.33 | 18.67 | |
| 1 | 9 | 0.11 | 23.72 | |
| 2 | 1 | 2.00 | -128.00 | |
| 2 | 3 | 0.67 | 0.00 | 3x-2 |
| 2 | 9 | 0.22 | 21.95 | |
| 3 | 1 | 3.00 | 0.00 | x-3 |
| 4 | 1 | 4.00 | 840.00 | |
| 4 | 3 | 1.33 | -66.67 | |
| 4 | 9 | 0.44 | 13.88 | |
| 6 | 1 | 6.00 | 7680.00 | |
| 8 | 1 | 8.00 | 28600.00 | |
| 8 | 3 | 2.67 | -93.33 | |
| 8 | 9 | 0.89 | -18.97 | |
| 12 | 1 | 12.00 | 162792.00 | |
| 24 | 1 | 24.00 | 2828280.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms In our case this means that 9x4-9x3-58x2+4x+24 can be divided by 4 different polynomials,including by x-3
Polynomial Long Division :
4.2 Polynomial Long Division Dividing : 9x4-9x3-58x2+4x+24 ("Dividend") By : x-3 ("Divisor")
| dividend | 9x4 | - | 9x3 | - | 58x2 | + | 4x | + | 24 |
| - divisor | * 9x3 | 9x4 | - | 27x3 | |||||
| remainder | 18x3 | - | 58x2 | + | 4x | + | 24 | ||
| - divisor | * 18x2 | 18x3 | - | 54x2 | |||||
| remainder | - | 4x2 | + | 4x | + | 24 | |||
| - divisor | * -4x1 | - | 4x2 | + | 12x | ||||
| remainder | - | 8x | + | 24 | |||||
| - divisor | * -8x0 | - | 8x | + | 24 | ||||
| remainder | 0 |
Quotient : 9x3+18x2-4x-8 Remainder: 0
Polynomial Roots Calculator :
4.3 Find roots (zeroes) of : F(x) = 9x3+18x2-4x-8 See theory in step 4.1 In this case, the Leading Coefficient is 9 and the Trailing Constant is -8. The factor(s) are: of the Leading Coefficient : 1,3 ,9 of the Trailing Constant : 1 ,2 ,4 ,8 Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | 5.00 | |
| -1 | 3 | -0.33 | -5.00 | |
| -1 | 9 | -0.11 | -7.35 | |
| -2 | 1 | -2.00 | 0.00 | x+2 |
| -2 | 3 | -0.67 | 0.00 | 3x+2 |
| -2 | 9 | -0.22 | -6.32 | |
| -4 | 1 | -4.00 | -280.00 | |
| -4 | 3 | -1.33 | 8.00 | |
| -4 | 9 | -0.44 | -3.46 | |
| -8 | 1 | -8.00 | -3432.00 | |
| -8 | 3 | -2.67 | -40.00 | |
| -8 | 9 | -0.89 | 3.46 | |
| 1 | 1 | 1.00 | 15.00 | |
| 1 | 3 | 0.33 | -7.00 | |
| 1 | 9 | 0.11 | -8.21 | |
| 2 | 1 | 2.00 | 128.00 | |
| 2 | 3 | 0.67 | 0.00 | 3x-2 |
| 2 | 9 | 0.22 | -7.90 | |
| 4 | 1 | 4.00 | 840.00 | |
| 4 | 3 | 1.33 | 40.00 | |
| 4 | 9 | 0.44 | -5.43 | |
| 8 | 1 | 8.00 | 5720.00 | |
| 8 | 3 | 2.67 | 280.00 | |
| 8 | 9 | 0.89 | 8.99 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms In our case this means that 9x3+18x2-4x-8 can be divided by 3 different polynomials,including by 3x-2
Polynomial Long Division :
4.4 Polynomial Long Division Dividing : 9x3+18x2-4x-8 ("Dividend") By : 3x-2 ("Divisor")
| dividend | 9x3 | + | 18x2 | - | 4x | - | 8 |
| - divisor | * 3x2 | 9x3 | - | 6x2 | |||
| remainder | 24x2 | - | 4x | - | 8 | ||
| - divisor | * 8x1 | 24x2 | - | 16x | |||
| remainder | 12x | - | 8 | ||||
| - divisor | * 4x0 | 12x | - | 8 | |||
| remainder | 0 |
Quotient : 3x2+8x+4 Remainder: 0
Trying to factor by splitting the middle term
4.5 Factoring 3x2+8x+4 The first term is, 3x2 its coefficient is 3 .The middle term is, +8x its coefficient is 8 .The last term, "the constant", is +4 Step-1 : Multiply the coefficient of the first term by the constant 3 • 4 = 12 Step-2 : Find two factors of 12 whose sum equals the coefficient of the middle term, which is 8 .
| -12 | + | -1 | = | -13 | |
| -6 | + | -2 | = | -8 | |
| -4 | + | -3 | = | -7 | |
| -3 | + | -4 | = | -7 | |
| -2 | + | -6 | = | -8 | |
| -1 | + | -12 | = | -13 | |
| 1 | + | 12 | = | 13 | |
| 2 | + | 6 | = | 8 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 2 and 6 3x2 + 2x + 6x + 4Step-4 : Add up the first 2 terms, pulling out like factors : x • (3x+2) Add up the last 2 terms, pulling out common factors : 2 • (3x+2) Step-5 : Add up the four terms of step 4 : (x+2) • (3x+2) Which is the desired factorization
Final result :
(3x + 2) • (x + 2) • (3x - 2) • (x - 3)Từ khóa » G(x)=3(4-9x)^4
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