* For All 3 Trials Find The Moles Of KHC8H4O4 Using The ...
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- 20.04.2021
- Chemistry
- Secondary School
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s02371joshuaprince47 s02371joshuaprince47 Answer:
Explanation:
Your goal here is to standardize a solution of sodium hydroxide,
NaOH
, by using potassium hydrogen phthalate,
KHP
.
Your starting point here is the balanced chemical equation for this neutralization reaction
KHP
(aq]
+
NaOH
(aq]
→
KNaP
(aq]
+
H
2
O
(l]
The important thing to notice here is that you have a
1
:
1
mole ratio between the two reactants. This tells you that at you can reach the equivalence point by reacting equal number of moles of
KHP
and of
NaOH
.
You start with
0.5100 g
of
KHP
. To get the molar amount of acid used for the experiment, use its molar mass
0.5100
g
⋅
molar mass of KHP
1 mole KHP
204.22
g
=
0.0024973 moles KHP
So, you know that at equivalence point, the reaction will consume
0.0024973
moles of
KHP
and
0.0024973
moles of
NaOH
, since that's what the
1
:
1
mole ratio tells you.
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