* For All 3 Trials Find The Moles Of KHC8H4O4 Using The ...

charlie209347 charlie209347

• 20.04.2021
• Chemistry
• Secondary School

answered • expert verified * For all 3 trials find the moles of KHC8H4O4 using the grams of KHC8H4O4. Show all work! * Use the mole ratio from question 1 to find the moles of NaOH used. Remember, in a 1:1 ratio if we use 1 mole of KHC8H4O4, then we use 1 mole of NaOH. Record the moles of NaOH used in each trial below. Trial 1 ________________ Trial 2 ________________ Trial 3 ________________ PLEASE, PLEASE HELP ME OUT! WORTH 30 POINTS:) See answer s02371joshuaprince47 s02371joshuaprince47

Answer:

Explanation:

Your goal here is to standardize a solution of sodium hydroxide,  

NaOH

, by using potassium hydrogen phthalate,  

KHP

.

Your starting point here is the balanced chemical equation for this neutralization reaction

KHP

(aq]

+

NaOH

(aq]

→

KNaP

(aq]

+

H

2

O

(l]

The important thing to notice here is that you have a  

1

:

1

mole ratio between the two reactants. This tells you that at you can reach the equivalence point by reacting equal number of moles of  

KHP

and of  

NaOH

.

You start with  

0.5100 g

of  

KHP

. To get the molar amount of acid used for the experiment, use its molar mass

0.5100

g

⋅

molar mass of KHP



1 mole KHP

204.22

g

=

0.0024973 moles KHP

So, you know that at equivalence point, the reaction will consume  

0.0024973

moles of  

KHP

and  

0.0024973

moles of  

NaOH

, since that's what the  

1

:

1

mole ratio tells you.

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