For The Function F ( X ) = − 5x^2 − 2x , Evaluate And Fully Simplify ...

Subject ZIP Search Search Find an Online Tutor Now Ask Ask a Question For Free Login Calculus Precalculus For the function f ( x ) = − 5x^2 − 2x , evaluate and fully simplify each of the following

For the function f ( x ) = − 5x^2 − 2x , evaluate and fully simplify each of the following

f(x+h)=

f(x+h)−f(x)/h=

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Firstly, you want to identify f(x+h). Back in algebra 2, we learned that f(x+h) means we add h to every x in our function.

f(x)= -5x2 - 2x

f(x+h) = -5(x+h)2 -2(x+h)

Now our difference quotient is (f(x+h)-f(x))/(h). Previously we found f(x+h), and we know f(x), so lets plug it in.

[f(x+h)-f(x)] / (h) = [-5(x+h)2 -2(x+h) - (-5x2- 2x)] / h

Lets simplify:

  1. -5(x+h)2 = -5(x+h)(x+h) = -5(x2 +2xh+h2) = -5x2- 10xh- 5h2
  2. -2(x+h) = -2x - 2h

So that,

[f(x+h)-f(x)] / (h) = [-5x2- 10xh- 5h2 - 2x - 2h - (-5x2- 2x)] / (h) FOIL and Distribute -2

= [-5x2- 10xh- 5h2 - 2x - 2h + 5x2+2x] / (h) Distribute the negitive

= [- 10xh - 5h2 - 2h ] / (h) Add like terms to cancel out terms that do not contain an h

= [h(- 10x-5h-2)] / (h) Factor out an h

= - 10x-5h-2 Simplify

The difference quiotent for f(x)=-5x2-2 is [f(x+h)-f(x)]/(h) = -10x-5h-2

If anything is incorrect, please let me know and I will promptly correct it. :)

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f(x+h) = -5(x+h)2-2(x+h) = -5(x2+2xh+h2)-2x-2h = -5x2-10xh-5h2-2x-2h

f(x+h)-f(x) = -5x2-10xh-5h2-2x-2h +5x2+2x = -10xh-5h2-2h

(f(x+h)-f(x))/h = -10x-5h-2

Upvote 0 Downvote Add comment More Report f ( x ) = − 5x^2 − 2xf ( x+h ) = − 5(x+h)^2 − 2(x+h)

(f ( x+h )-f(x))/h=(− 5(x+h)^2 − 2(x+h)-(− 5x^2 − 2x))/h

= (-5x^2-10xh-5h^2-2x-2h+5x^2+2x)/h

=(-10xh-5h^2-2h)/h=-10x-5h-2

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