For The Redox Reaction MnO4 + C2O42 + H + To Mn2 + ... - Vedantu

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• For the redox reaction MnO4 + ...

AnswerQuestion Answers for Class 12Class 12 BiologyClass 12 ChemistryClass 12 EnglishClass 12 MathsClass 12 PhysicsClass 12 Social ScienceClass 12 Business StudiesClass 12 EconomicsQuestion Answers for Class 11Class 11 EconomicsClass 11 Computer ScienceClass 11 BiologyClass 11 ChemistryClass 11 EnglishClass 11 MathsClass 11 PhysicsClass 11 Social ScienceClass 11 AccountancyClass 11 Business StudiesQuestion Answers for Class 10Class 10 ScienceClass 10 EnglishClass 10 MathsClass 10 Social ScienceClass 10 General KnowledgeQuestion Answers for Class 9Class 9 General KnowledgeClass 9 ScienceClass 9 EnglishClass 9 MathsClass 9 Social ScienceQuestion Answers for Class 8Class 8 ScienceClass 8 EnglishClass 8 MathsClass 8 Social ScienceQuestion Answers for Class 7Class 7 ScienceClass 7 EnglishClass 7 MathsClass 7 Social ScienceQuestion Answers for Class 6Class 6 ScienceClass 6 EnglishClass 6 MathsClass 6 Social ScienceQuestion Answers for Class 5Class 5 ScienceClass 5 EnglishClass 5 MathsClass 5 Social ScienceQuestion Answers for Class 4Class 4 ScienceClass 4 EnglishClass 4 MathsFor the redox reaction, $Mn{O_4}^ - + {C_2}{O_4}^{2 - } + {H^ + } \to M{n^{2 + }} + C{O_2} + {H_2}O$ , the correct coefficients of the reactants for the balanced equation areA. $Mn{O_4}^ - = 2,{C_2}{O_4}^{2 - } = 16,{H^ + } = 5$B. $Mn{O_4}^ - = 16,{C_2}{O_4}^{2 - } = 5,{H^ + } = 2$C. $Mn{O_4}^ - = 5,{C_2}{O_4}^{2 - } = 16,{H^ + } = 2$D. $Mn{O_4}^ - = 2,{C_2}{O_4}^{2 - } = 5,{H^ + } = 16$AnswerVerified574.8k+ viewsHint: The unbalanced given reaction is a redox reaction that is oxidation and reduction are occurring simultaneously in the reaction. Here the reduction of permanganate ion is happening that means permanganate ion is acting as an oxidizing agent in acidic solution. Complete Step by step answer: n this reaction, $Mn{O_4}^ - + {C_2}{O_4}^{2 - } + {H^ + } \to M{n^{2 + }} + C{O_2} + {H_2}O$, on the left side manganese Mn exhibits 7 positive charge and on the right side it contains 2 positive charge. Thus manganese is getting reduced. Carbon on the left side exhibits 3 positive charges and on the right it has 4 positive charges, hence carbon is getting oxidized. So the reaction can be divided in two half reactions one is oxidation reaction and the other is reduction reaction.In Reduction half reaction $M{n^{7 + }}$ in $Mn{O_4}^ - $ becomes $M{n^{2 + }}$ by taking on five electrons. Any oxygen however should become ${H_2}O$ as a byproduct, and water cannot form without hydrogen ion, hence ${H^ + }$ must be added to the left side. On balancing the reaction 4 water molecules should be formed. So the balanced reduction half reaction now become-$Mn{O_4}^ - + 5e + 8{H^ + } \to M{n^{2 + }} + 4{H_2}O$In the oxidation half reaction, ${C_2}{O_4}^ - $ becomes $C{O_2}$ by giving two electrons. So the balanced half oxidation reaction should be- ${C_2}{O_4}^ - \to C{O_2} + 2e$On combining both half reactions, we have to balance the number of electrons, so multiply the reduction reaction by 2 and oxidation reaction by 5. And this will bring the total number of electrons to 10 on both the half reactions. By cancelling those 10 electrons from both reactions, the total full redox reaction will now become- $2Mn{O_4}^ - + 16{H^ + } + 5{C_2}{O_4}^ - \to 2M{n^{2 + }} + 10C{O_2} + 8{H_2}O$Hence the correct option will be D, $Mn{O_4}^ - = 2,{C_2}{O_4}^{2 - } = 5,{H^ + } = 16$Note: The manganese reduction reaction includes the gain of 10 electrons, whereas the oxalate oxidation reaction involves the loss of 10 electrons. The electrons therefore cancel. Practically speaking, the five oxalate ions transfer a total of 10 electrons to 2 permanganate ions. Recently Updated PagesMaster Class 11 Computer Science: Engaging Questions & Answers for SuccessMaster Class 11 Business Studies: Engaging Questions & Answers for SuccessMaster Class 11 Economics: Engaging Questions & Answers for SuccessMaster Class 11 English: Engaging Questions & Answers for SuccessMaster Class 11 Maths: Engaging Questions & Answers for SuccessMaster Class 11 Biology: Engaging Questions & Answers for SuccessMaster Class 11 Computer Science: Engaging Questions & Answers for SuccessMaster Class 11 Business Studies: Engaging Questions & Answers for SuccessMaster Class 11 Economics: Engaging Questions & Answers for SuccessMaster Class 11 English: Engaging Questions & Answers for SuccessMaster Class 11 Maths: Engaging Questions & Answers for SuccessMaster Class 11 Biology: Engaging Questions & Answers for Success

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