From The Equation CH4+2O2→CO2+2H2O I) What Volume Of Carbon ...

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AnswerQuestion Answers for Class 12Class 12 BiologyClass 12 ChemistryClass 12 EnglishClass 12 MathsClass 12 PhysicsClass 12 Social ScienceClass 12 Business StudiesClass 12 EconomicsQuestion Answers for Class 11Class 11 EconomicsClass 11 Computer ScienceClass 11 BiologyClass 11 ChemistryClass 11 EnglishClass 11 MathsClass 11 PhysicsClass 11 Social ScienceClass 11 AccountancyClass 11 Business StudiesQuestion Answers for Class 10Class 10 ScienceClass 10 EnglishClass 10 MathsClass 10 Social ScienceClass 10 General KnowledgeQuestion Answers for Class 9Class 9 General KnowledgeClass 9 ScienceClass 9 EnglishClass 9 MathsClass 9 Social ScienceQuestion Answers for Class 8Class 8 ScienceClass 8 EnglishClass 8 MathsClass 8 Social ScienceQuestion Answers for Class 7Class 7 ScienceClass 7 EnglishClass 7 MathsClass 7 Social ScienceQuestion Answers for Class 6Class 6 ScienceClass 6 EnglishClass 6 MathsClass 6 Social ScienceQuestion Answers for Class 5Class 5 ScienceClass 5 EnglishClass 5 MathsClass 5 Social ScienceQuestion Answers for Class 4Class 4 ScienceClass 4 EnglishClass 4 MathsFrom the equation $C{H_4} + 2{O_2} \to C{O_2} + 2{H_2}O$ i) what volume of carbon dioxide is produced by $200c{m^3}$ of methane?ii) What volume of Oxygen is required to completely burn $200c{m^3}$ of Methane?AnswerVerified498.6k+ viewsHint: Considering standard temperature and pressure (STP) conditions, we’ll consider the pressure to be 1 atmosphere and temperature to be 273.15K. At STP 1 mole of molecule occupies $22.4L$ of volume. This is the standard values we’ll consider for the given question.Complete answer: The given reaction is a combustion reaction. Combustion of hydrocarbons always leads to the formation of Carbon Dioxide and water. According to the balanced chemical reaction, we can infer that one mole of Methane required 2 moles of Oxygen to form 1 mol of Carbon Dioxide and 2 moles of water.i) Given that we have taken $200c{m^3}$ of methane. 1 mole of methane produces only 1 mole of carbon dioxide. Hence, we can say that: $1mol{\text{ }}C{H_4} = 1mol{\text{ }}C{O_2}$We know that one mole of molecule at STP occupies $22.4L$ of volume. We can say that, $22.4L{\text{ }}C{H_4} = 22.4L{\text{ C}}{{\text{O}}_2}$ $200c{m^3}{\text{ }}C{H_4} = \dfrac{{0.2 \times 22.4}}{{22.4}} = 0.2L = 200c{m^3}$of carbon dioxide.ii) According to the balanced chemical equation 1mole of methane requires 2 moles of Oxygen. We can say that: $1mol{\text{ }}C{H_2}(22.4L) = 2mol{\text{ }}{O_2}(2 \times 22.4)$Therefore, $200c{m^3}$ or $0.2L$ of methane will require $ = \dfrac{{0.2 \times 2 \times 22.4}}{{22.4}} = 0.4L = 400c{m^3}$ of Oxygen. Note: According to Avogadro’s hypothesis at constant Pressure and Temperature, all gases contain the same number of particles. Since the number of particles are almost the same, the volume occupied by them will also be the same i.e., $22.4L$ . This volume will change when a gas is heated as the gas expands on heating, as the molecule moves at a faster rate. Also, change in pressure (expansion or compression) changes the volume of the gas. Hence, while making this assumption the Temperature and pressure is considered to be constant at 272.15K and 1 atmosphere respectively. Recently Updated PagesMaster Class 9 General Knowledge: Engaging Questions & Answers for SuccessMaster Class 9 Social Science: Engaging Questions & Answers for SuccessMaster Class 9 English: Engaging Questions & Answers for SuccessMaster Class 9 Maths: Engaging Questions & Answers for SuccessMaster Class 9 Science: Engaging Questions & Answers for SuccessClass 9 Question and Answer - Your Ultimate Solutions GuideMaster Class 9 General Knowledge: Engaging Questions & Answers for SuccessMaster Class 9 Social Science: Engaging Questions & Answers for SuccessMaster Class 9 English: Engaging Questions & Answers for SuccessMaster Class 9 Maths: Engaging Questions & Answers for SuccessMaster Class 9 Science: Engaging Questions & Answers for SuccessClass 9 Question and Answer - Your Ultimate Solutions Guide

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