G(x)=4x^2-484 - Solution
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Solution for G(x)=4x^2-484 equation:
(G)=4G^2-484 We move all terms to the left: (G)-(4G^2-484)=0 We get rid of parentheses -4G^2+G+484=0 a = -4; b = 1; c = +484;Δ = b2-4acΔ = 12-4·(-4)·484Δ = 7745The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{7745}}{2*-4}=\frac{-1-\sqrt{7745}}{-8} $ $G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{7745}}{2*-4}=\frac{-1+\sqrt{7745}}{-8} $See similar equations:
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