G(x)=(-5x-1)(2x+8) - Solution
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Solution for G(x)=(-5x-1)(2x+8) equation:
(G)=(-5G-1)(2G+8) We move all terms to the left: (G)-((-5G-1)(2G+8))=0 We multiply parentheses .. -((-10G^2-40G-2G-8))+G=0 We calculate terms in parentheses: -((-10G^2-40G-2G-8)), so: (-10G^2-40G-2G-8) We get rid of parentheses -10G^2-40G-2G-8 We add all the numbers together, and all the variables -10G^2-42G-8 Back to the equation: -(-10G^2-42G-8) We get rid of parentheses 10G^2+42G+G+8=0 We add all the numbers together, and all the variables 10G^2+43G+8=0 a = 10; b = 43; c = +8;Δ = b2-4acΔ = 432-4·10·8Δ = 1529The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-\sqrt{1529}}{2*10}=\frac{-43-\sqrt{1529}}{20} $ $G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+\sqrt{1529}}{2*10}=\frac{-43+\sqrt{1529}}{20} $See similar equations:
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