Giải Bài Tập 2 Trang 177 Sgk Toán 4 - Tech12h

01 Đề bài:

Bài 2: Trang 177 - sgk toán lớp 4

Tính:

a) \(\frac{2}{5}\) + \(\frac{3}{10}\) - \(\frac{1}{2}\) ;

b) \(\frac{8}{11}\) + \(\frac{8}{33}\) x \(\frac{3}{4}\) ;

c) \(\frac{7}{9}\) x \(\frac{3}{14}\) : \(\frac{5}{8}\) ;

d) \(\frac{5}{12}\) - \(\frac{7}{32}\) : \(\frac{21}{16}\) ;

02 Bài giải:

Bài 2:

a)

\(\frac{2}{5}\) + \(\frac{3}{10}\) - \(\frac{1}{2}\) = \(\frac{4}{10}\) + \(\frac{3}{10}\) - \(\frac{5}{10}\) = \(\frac{7}{10}\) - \(\frac{5}{10}\) = \(\frac{2}{10}\) = \(\frac{1}{5}\)

b)

\(\frac{8}{11}\) + \(\frac{8}{33}\) x \(\frac{3}{4}\) = \(\frac{8}{11}\) + \(\frac{2}{11}\) = \(\frac{10}{11}\)

c)

\(\frac{7}{9}\) x \(\frac{3}{14}\) : \(\frac{5}{8}\) = \(\frac{1}{6}\) : \(\frac{5}{8}\) = \(\frac{1}{6}\) x \(\frac{8}{5}\) = \(\frac{8}{30}\) = \(\frac{4}{15}\)

d)

\(\frac{5}{12}\) - \(\frac{7}{32}\) : \(\frac{21}{16}\) = \(\frac{5}{12}\) - \(\frac{7}{32}\) x \(\frac{16}{21}\) = \(\frac{5}{12}\) - \(\frac{1}{6}\) = \(\frac{5}{12}\) - \(\frac{2}{12}\) = \(\frac{3}{12}\)

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