Given F(x)=4x-3, G(x)=1/x And H(x)= X^2-x, How Do You Find H(1/x)?

Given f(x)=4x-3, g(x)=1/x and h(x)= x^2-x, how do you find h(1/x)? Algebra Expressions, Equations, and Functions Function Notation

1 Answer

Jim G. Sep 13, 2017

#(1-x)/(x^2)#

Explanation:

#"to evaluate "h(1/x)" substitute "x=1/x" in "h(x)#

#rArrh(1/x)=(1/x)^2-1/x#

#color(white)(rArrh(1/x))=1/x^2-1/x#

#"we can express this as a single fraction"#

#"multiplt the numerator/denominator of "1/x" by "x#

#rArr1/x^2-x/x^2#

#"denominators are common so subtract the numerators"# #"leaving the denominator as it is."#

#rArrh(1/x)=1/x^2-x/x^2=(1-x)/x^2#

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