Given, NH3(g) + 3Cl2(g) Leftharpoons NCl3(g) + 3HCl(g)

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4. Given, NH3(g) + 3Cl2(g) leftharpoons NCl3(g) + 3HCl(g) - Δ H1 N2(g) + 3H2(g) leftharpoons 2NH3(g) - Δ H2 H2(g) + Cl2(g) leftharpoons 2HCl(g) - Δ H3 The heat of formation of NCl3(g) in terms of Δ H1, Δ H2 and Δ H3 is

Q. Given, NH3​(g)+3Cl2​(g)⇌NCl3​(g)+3HCl(g)−ΔH1​ N2​(g)+3H2​(g)⇌2NH3​(g)−ΔH2​ H2​(g)+Cl2​(g)⇌2HCl(g)−ΔH3​ The heat of formation of NCl3​(g) in terms of ΔH1​,ΔH2​ and ΔH3​ is 4206 165 AMUAMU 2011Thermodynamics Report Error A

ΔHf​=−ΔH1​+21​ΔH2​−23​ΔH3​

29% B

ΔHf​=−ΔH1​+21​ΔH2​+23​ΔH3​

27% C

ΔHf​=−ΔH1​−21​ΔH2​−23​ΔH3​

14% D

None of the above

30%

Solution:

NH3​(g)+3Cl2​(g)⇌NCl3​(g)+3HCl(g); −ΔH1​...(i) N2​(g)+3H2​(g)⇌2NH3​(g); −ΔH2​...(ii) H2​(g)+Cl2​(g)⇌2HCl(g) ; +ΔH3​...(iii) Multiply Eq. (i) by 2 and Eq. (iii) by 3, add Eq. (i) to Eq. (ii) and subtract Eq. (iii) to get the heat of formation of NCl3​(g); N2​+3Cl2​⇌2NCl3​ 2ΔHf​=2×(−ΔH1​)+(−ΔH2​)−3×(+ΔH3​) or ΔHf​=−ΔH1​−21​ΔH2​−23​ΔH3​