Given That G(x)=3x^2+3x+20, Find Each Of The Following G(4) And G(p+4)

Subject ZIP Search Search Find an Online Tutor Now Ask Ask a Question For Free Login Algebra given that g(x)=3x^2+3x+20, find each of the following g(4) and g(p+4) I am needing help in finding what g(4) and g(p+4) is equivalent to. The problem gives the information stating that g(x) is equal to 3x squared plus 3x+ 20 Follow • 3 Add comment More Report

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Best Newest Oldest By: Best Newest Oldest g(x)=3x^2+3x+20 now replace x with 4 then g(4)=3*(4^2)+3*4+20 =3*16+12+20 = 48+12+20 = 80 ============ Now replace x with (p+4), then g(p+4)=3*(p+4)^2+3*(p+4)+20 (a+b)^2=a^2+2ab+b^2 (p+4)^2=p^2+2*p*4+4^2 =3[p^2+2*p*4+4^2]+3p+3*4+20 =3[p^2+8p+16]+3p+12+20 =[3*p^2+3*8p+3*16]+3p+32 =3*p^2+24p+48+3p+32 =3*p^2+27p+80 =3p2+27p+80 ============================ Upvote • 1 Downvote Add comment More Report Plug in 4 into x to get g(4). g(4)=3(4)^2+3(4)+20=3(16)+12+20=80 Plug in p+4 into x to get g(p+4) g(p+4)=3(p+4)^2+3(p+4)+20 =3(p^2+8p+16)+3p+12+20 =3p^2+24p+48+3p+32 =3p^2+27p+80 now: g(4)+g(p+4) = 80+3p^2+27p+80 =3p^2+27p+160 Upvote • 0 Downvote Add comment More Report

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