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Answer to: Calculate the pH of a solution with H+ = 1 x 10-9 M. By signing up, you'll get thousands of step-by-step solutions to your homework...
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The H+ ion concentration = -(log 10–9)= -9(-log 10)= -9× -1= 9. So the pH of the solution is 9.The pOH of the solution is 5. Concentration of OH- ion is 10–5 M. The concentration of H+ in two solutions are a) 1 × 10^-3 mol dm What is the pH of a solution that has a hydrogen ion concentration of ... What is the pH of a solution with an H+ concentration of 10 − 12 m? Would a solution with a [H+] concentration of 1 X 10-11 have a pH ... Các kết quả khác từ www.quora.com
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1 x 10-4. 4. 1 x 10-10. 10. 1 x 10-5. 5. 1 x 10-9. 9. 1 x 10-6 ... Where [HA] is the reactant acid concentration, [H+] (also sometimes represented as ...
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[H+]=1₁0x10=14/5.5 × 10-3 = 1.8 × 10-12. 4. A solution has an [OH ] = 3.71 × 106 M. Find the [H], the. {1+] = 1:0×10=4/3.71x10-6 = 2.70 x 10-9.
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pure water the concentration of hydrogen ions is 1 x 10-7 M. Thus, the pH of a solution of pure ... Solution: [H+] = 1 x 10-14 / 1 x 10-9 = 1 x 10-5 M.
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In the pH scale, acids are pH7. Each increase in pH makes something less acidic (or more basic) by 10. Therefore [H+]=1x10^ ...
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The hydronium ion concentration can be found from the pH by the reverse of the mathematical operation employed to find ... [H3O+] = 10-8.34 = 4.57 x 10-9 M.
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•in pure water---[H+] [OH-] = x2 = 10-14; Hence [H+] = [OH-] = 1 x 10-7 ... pH for strong acid and strong base determined by moles of H+ or OH-.
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2 thg 5, 2020 · Here it helps to rewrite the concentration as 1.0 x 10-4 M because ... An acid should have a pH much less than seven (usually one to three) ...
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The hydroxide ion concentration of a solution is 1.0 × 10 9 M. What is the pH of this solution? State whether the given solution is acidic, ...
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Using another log rule, we can express each side of this equation as an exponent of 10 and we get: 10^pH = 10^log ([H+]^-1). ... Multiplying each side by [H+] and ...
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1. = рон. B. 2. Calculate the pH of the following. a) [H+] = 1.0 x 102 M рн. PH=2. POH = 6 ... pH = -log (3,6×10-9)= 8,4 ... pOH = -log (5.01×10-1) = 10.3.
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