H=-16t2+8t+8 - Solution

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H=-16t2+8t+8

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Solution for H=-16t2+8t+8 equation:

=-16H^2+8H+8 We move all terms to the left: -(-16H^2+8H+8)=0 We get rid of parentheses 16H^2-8H-8=0 a = 16; b = -8; c = -8;Δ = b2-4acΔ = -82-4·16·(-8)Δ = 576The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$ $H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-24}{2*16}=\frac{-16}{32} =-1/2 $ $H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+24}{2*16}=\frac{32}{32} =1 $

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