H(n)=2n-3 - Solution
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Solution for H(n)=2n-3 equation:
(H)=2H-3 We move all terms to the left: (H)-(2H-3)=0 We get rid of parentheses H-2H+3=0 We add all the numbers together, and all the variables -1H+3=0 We move all terms containing H to the left, all other terms to the right -H=-3 H=-3/-1 H=+3See similar equations:
| 5x=3x+6=-10 | | 2(3x+2)=-5(4x-5) | | 4(5x+1)=-5(5x-3) | | 8-25s-2.375=10 | | 3x-66=30 | | 6+4n=226 | | X2+3x-4=50 | | -6r=-66 | | 9r+10=40-r | | 4(5x+1)=-5(5x-3 | | 6*4n=226 | | 3(3x+5)+10=-20 | | 7n-13=5n=7 | | 5(5x+1)=-4(3x-5) | | 2x-3=2x-5x | | 6p-2=2p+18 | | 6r-2=3r+13 | | 90-13m=194 | | 3(3x+3)=-4(3x-5) | | 3(x-6)-4(x=3) | | 4d-3=27 | | 225=27x=18 | | K(n)=-2-5 | | 5p-7=9p-27 | | 2r+7=22-r | | H(n)=-3n-4 | | 34b+15=9b | | 114=m+99 | | -2(x-5)+4=7x+14-3x | | 7p-6=8p-8 | | 11r-20=10r-10 | | 12m+23=23m+2. |
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