H2C2O4 + MnO4{-} + H{+} = Mn{2+} + H2O + CO2 - ChemicalAid

Trang chủ » H2c2o4 + Mno4 + H = Co2 + Mn + H2o » H2C2O4 + MnO4{-} + H{+} = Mn{2+} + H2O + CO2 - ChemicalAid

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To balance the equation H2C2O4 + MnO4{-} + H{+} = Mn{2+} + H2O + CO2 using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a H2C2O4 + b MnO4- + c H+ = d Mn2+ + f H2O + g CO2

Step 2: Create a System of Equations

Create an equation for each element (H, C, O, Mn, e) where each term represents the number of atoms of the element in each reactant or product.

H: 2a + 0b + 1c = 0d + 2f + 0g C: 2a + 0b + 0c = 0d + 0f + 1g O: 4a + 4b + 0c = 0d + 1f + 2g Mn: 0a + 1b + 0c = 1d + 0f + 0g e: 0a + 1b + -1c = -2d + 0f + 0g

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination
  • 2a + 1c - 2f = 0
  • 2a - 1g = 0
  • 4a + 4b - 1f - 2g = 0
  • 1b - 1d = 0
  • 1b - 1c + 2d = 0
Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 2 0 1 0 -2 0 0] [ 2 0 0 0 0 -1 0] [ 4 4 0 0 -1 -2 0] [ 0 1 0 -1 0 0 0] [ 0 1 -1 2 0 0 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

  • a = 5 (H2C2O4)
  • b = 2 (MnO4{-})
  • c = 6 (H{+})
  • d = 2 (Mn{2+})
  • f = 8 (H2O)
  • g = 10 (CO2)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

5 H2C2O4 + 2 MnO4- + 6 H+ = 2 Mn2+ + 8 H2O + 10 CO2
Reactants Products
H1616✔️
C1010✔️
O2828✔️
Mn22✔️
e-4-4✔️
Since there is an equal number of each element in the reactants and products of 5H2C2O4 + 2MnO4{-} + 6H{+} = 2Mn{2+} + 8H2O + 10CO2, the equation is balanced.

Từ khóa » H2c2o4 + Mno4 + H = Co2 + Mn + H2o