HCN + NH3 3

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Chemistry 112

The hydrogen ion transfer is onto the ammonia, giving ammonium ion as the product. The other product is cyanide ion.

HCN(aq) + NH3(aq) → ← NH4+(aq) + CN–(aq)

We need to find Ka values using the Table of Acid Ionization Constants

Ka(acid) = 6.2×10–10

Ka(conjugate acid) = 5.6×10–10

Kc = Ka(acid)/Ka(conjugate acid) = (6.2×10–10)/(5.6×10–10) = 1.1 < 100

The reaction is an equilibrium.

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