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Offline nlee5687

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Heat
« on: November 15, 2007, 09:20:40 pm » Find Delta--H° for the reaction C3H8(g) + 5O2(g) ===> 3CO2(g) + 4H2O(l). Delta H° = -2046 kJ for the reaction, C3H8(g) + 5O2(g) ===> 3CO2(g) + 4H2O(g), and the heat of vaporization of water is 44.0 kJ/mol. Can someone evaluate my answer to see if it is correct?4 x 44 = 176-2046+176 = -1870 kJ Logged

Offline LQ43

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Re: Heat
« Reply #1 on: November 15, 2007, 10:22:23 pm » Quote from: nlee5687 on November 15, 2007, 09:20:40 pm
Find Delta--H° for the reaction C3H8(g) + 5O2(g) ===> 3CO2(g) + 4H2O(l). Delta H° = -2046 kJ for the reaction, C3H8(g) + 5O2(g) ===> 3CO2(g) + 4H2O(g), and the heat of vaporization of water is 44.0 kJ/mol.
heat of vap of H2O is H2O(l) --> H2O(g) delta H = 44 kJbut need H2O(g) --> H2O(l) so delta H = -44 kJso -2046 + (4 x -44kJ) Logged
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