Heat Of Reaction For C6H12O6(s) + 6O2 (g) → 6CO2(g) + 6H2O(v) At ...
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Heat of reaction for C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(v) at constant pressure is -651 kcal at 17°C. Calculate the heat of reaction at constant volume at 17°C.
Open in AppSolutionVerified by TopprAs we know,△H=△E+△nRTHere, △H=−651×103 calR=2calT=290Kand △n=6+6−6=6∴−651×103=△E+6×2×290△E=−651000−3480=−654.480∴△E=−654.48Kcal
Was this answer helpful?5Similar QuestionsQ1Heat of reaction for C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(v) at constant pressure is -651 kcal at 17°C. Calculate the heat of reaction at constant volume at 17°C.
View SolutionQ2Heat of reaction for C6H12O6(s)+6O2→6CO2(g)+6H2O(v) at constant pressure is −651Kcal at 17∘C. What is the heat of reaction at constant volume at 17∘C?
View SolutionQ3Heat of reaction for, C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(v) at constant pressure is −651kcal at 170C. Calculate the heat of reaction at constant volume at 170C View SolutionQ4Heat of reaction for: C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(g), at constant pressure is −651Kcal at 17oC. Calculate the heat of reaction at constant volume at 17oC.View SolutionQ5Heat of reaction for C6H12O6(s)+6O2→6CO2(g)+6H2O(v) at constant pressure is −651Kcal at 17∘C. What is the heat of reaction at constant volume at 17∘C?
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