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AnswerQuestion Answers for Class 12Class 12 BiologyClass 12 ChemistryClass 12 EnglishClass 12 MathsClass 12 PhysicsClass 12 Social ScienceClass 12 Business StudiesClass 12 EconomicsQuestion Answers for Class 11Class 11 EconomicsClass 11 Computer ScienceClass 11 BiologyClass 11 ChemistryClass 11 EnglishClass 11 MathsClass 11 PhysicsClass 11 Social ScienceClass 11 AccountancyClass 11 Business StudiesQuestion Answers for Class 10Class 10 ScienceClass 10 EnglishClass 10 MathsClass 10 Social ScienceClass 10 General KnowledgeQuestion Answers for Class 9Class 9 General KnowledgeClass 9 ScienceClass 9 EnglishClass 9 MathsClass 9 Social ScienceQuestion Answers for Class 8Class 8 ScienceClass 8 EnglishClass 8 MathsClass 8 Social ScienceQuestion Answers for Class 7Class 7 ScienceClass 7 EnglishClass 7 MathsClass 7 Social ScienceQuestion Answers for Class 6Class 6 ScienceClass 6 EnglishClass 6 MathsClass 6 Social ScienceQuestion Answers for Class 5Class 5 ScienceClass 5 EnglishClass 5 MathsClass 5 Social ScienceQuestion Answers for Class 4Class 4 ScienceClass 4 EnglishClass 4 MathsHow can I balance this equation? ${\text{_}}{{\text{N}}_{\text{2}}}{\text{ + _}}{{\text{H}}_{\text{2}}} \to {\text{N}}{{\text{H}}_{\text{3}}}$AnswerVerified564.3k+ viewsHint: For the balancing of an equation we have to maintain equal molecularity of each atom in the left hand side or reactant side as well as in the right hand side or product side.Complete Solution :In the given equation ${\text{_}}{{\text{N}}_{\text{2}}}{\text{ + _}}{{\text{H}}_{\text{2}}} \to {\text{N}}{{\text{H}}_{\text{3}}}$-Nitrogen (${{\text{N}}_{\text{2}}}$) and hydrogen (${{\text{H}}_{\text{2}}}$) gas reacts together for the formation of ammonia (${\text{N}}{{\text{H}}_3}$) gas.-On the reactant side two nitrogen atoms are present but on the product side only one nitrogen atom is present. So for balancing the amount of nitrogen on both the sides, we have to multiply nitrogen by 2 on the right hand side of the given chemical reaction.-Similarly, the amount of hydrogen is also not equal on both sides of the chemical reaction as two hydrogen atoms are present on the reactant side and three are present on the product side. So for balancing the amount of hydrogen on both the sides, we have to multiply hydrogen by 3 on the left hand side and by 2 on the right hand side of the given chemical reaction.-So, balanced form of above given chemical reaction is as follow:${{\text{N}}_{\text{2}}}{\text{ + 3}}{{\text{H}}_{\text{2}}} \to 2{\text{N}}{{\text{H}}_{\text{3}}}$Note: Some of you may get confused in between the order of reaction and molecularity, but these two things are totally different. As order of reaction is an experimental quantity and molecularity is a theoretical quantity. But these two things are the same for elementary reactions or single step reactions.Recently Updated PagesMaster Class 11 English: Engaging Questions & Answers for SuccessMaster Class 11 Maths: Engaging Questions & Answers for SuccessMaster Class 11 Biology: Engaging Questions & Answers for SuccessMaster Class 11 Physics: Engaging Questions & Answers for SuccessMaster Class 11 Accountancy: Engaging Questions & Answers for SuccessClass 11 Question and Answer - Your Ultimate Solutions GuideMaster Class 11 English: Engaging Questions & Answers for SuccessMaster Class 11 Maths: Engaging Questions & Answers for SuccessMaster Class 11 Biology: Engaging Questions & Answers for SuccessMaster Class 11 Physics: Engaging Questions & Answers for SuccessMaster Class 11 Accountancy: Engaging Questions & Answers for SuccessClass 11 Question and Answer - Your Ultimate Solutions Guide

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