How Does (kg/m^3) * (m/s^2) * (m) Come Out To Be Units Of N/m^2?

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Learn more about Teams How does (kg/m^3) * (m/s^2) * (m) come out to be units of N/m^2? [closed] Ask Question Asked 11 years, 2 months ago Modified 11 years, 2 months ago Viewed 34k times 0 $\begingroup$ Closed. This question is off-topic. It is not currently accepting answers.

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To me it seems to come out to be kg/(m*s^2). Is this somehow equivalent to N/m^2?

  • homework-and-exercises
  • units
  • unit-conversion
Share Cite Improve this question Follow edited Sep 10, 2013 at 9:35 Mostafa's user avatar Mostafa 4,0142 gold badges27 silver badges44 bronze badges asked Sep 10, 2013 at 2:17 gbanks's user avatar gbanksgbanks 111 gold badge1 silver badge3 bronze badges $\endgroup$ 1
  • 3 $\begingroup$ Use the fact that N = kg m/s^2 . $\endgroup$ – Abhimanyu Pallavi Sudhir Commented Sep 10, 2013 at 5:17
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Sorted by: Reset to default Highest score (default) Date modified (newest first) Date created (oldest first) 4 $\begingroup$

By definition

1 N = 1 kg m/s^2

To remember this, remember F = ma. The left hand side has units of force. The right hand side is kg * (m/s^2).

dividing both sides by m^2, we get

1 N/m^2 = 1 kg / (m s^2)

Share Cite Improve this answer Follow answered Sep 10, 2013 at 2:26 Mark Eichenlaub's user avatar Mark EichenlaubMark Eichenlaub 53.6k15 gold badges143 silver badges242 bronze badges $\endgroup$ Add a comment |

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