How Does (kg/m^3) * (m/s^2) * (m) Come Out To Be Units Of N/m^2?
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Learn more about Teams How does (kg/m^3) * (m/s^2) * (m) come out to be units of N/m^2? [closed] Ask Question Asked 11 years, 3 months ago Modified 11 years, 3 months ago Viewed 34k times 0 $\begingroup$ Closed. This question is off-topic. It is not currently accepting answers.Homework-like questions should ask about a specific physics concept and show some effort to work through the problem. We want our questions to be useful to the broader community, and to future users. See our meta site for more guidance on how to edit your question to make it better
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Improve this questionTo me it seems to come out to be kg/(m*s^2). Is this somehow equivalent to N/m^2?
Share Cite Improve this question Follow edited Sep 10, 2013 at 9:35 Mostafa 4,0242 gold badges27 silver badges45 bronze badges asked Sep 10, 2013 at 2:17 gbanksgbanks 111 gold badge1 silver badge3 bronze badges $\endgroup$ 1- 3 $\begingroup$ Use the fact that N = kg m/s^2 . $\endgroup$ – Abhimanyu Pallavi Sudhir Commented Sep 10, 2013 at 5:17
1 Answer
Sorted by: Reset to default Highest score (default) Date modified (newest first) Date created (oldest first) 4 $\begingroup$By definition
1 N = 1 kg m/s^2
To remember this, remember F = ma. The left hand side has units of force. The right hand side is kg * (m/s^2).
dividing both sides by m^2, we get
1 N/m^2 = 1 kg / (m s^2)
Share Cite Improve this answer Follow answered Sep 10, 2013 at 2:26 Mark EichenlaubMark Eichenlaub 53.7k15 gold badges143 silver badges243 bronze badges $\endgroup$ Add a comment |Not the answer you're looking for? Browse other questions tagged
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