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AnswerQuestion Answers for Class 12Class 12 BiologyClass 12 ChemistryClass 12 EnglishClass 12 MathsClass 12 PhysicsClass 12 Social ScienceClass 12 Business StudiesClass 12 EconomicsQuestion Answers for Class 11Class 11 EconomicsClass 11 Computer ScienceClass 11 BiologyClass 11 ChemistryClass 11 EnglishClass 11 MathsClass 11 PhysicsClass 11 Social ScienceClass 11 AccountancyClass 11 Business StudiesQuestion Answers for Class 10Class 10 ScienceClass 10 EnglishClass 10 MathsClass 10 Social ScienceClass 10 General KnowledgeQuestion Answers for Class 9Class 9 General KnowledgeClass 9 ScienceClass 9 EnglishClass 9 MathsClass 9 Social ScienceQuestion Answers for Class 8Class 8 ScienceClass 8 EnglishClass 8 MathsClass 8 Social ScienceQuestion Answers for Class 7Class 7 ScienceClass 7 EnglishClass 7 MathsClass 7 Social ScienceQuestion Answers for Class 6Class 6 ScienceClass 6 EnglishClass 6 MathsClass 6 Social ScienceQuestion Answers for Class 5Class 5 ScienceClass 5 EnglishClass 5 MathsClass 5 Social ScienceQuestion Answers for Class 4Class 4 ScienceClass 4 EnglishClass 4 MathsHow many isomers of molecular formula ${{C}_{3}}{{H}_{9}}N$ will liberate ${{N}_{2}}$ gas on treatment with $HN{{O}_{2}}$ .a.) Oneb.) Three c.) Twod.) Five AnswerVerified571.2k+ viewsHint: Isomers are defined as the molecules which have the same molecular formula but different molecular geometries. There are two types of isomers such as conformational isomers and constitutional isomers.Complete Solution :In the given formulae ${{C}_{3}}{{H}_{9}}N$, four isomers are possible. They are propan-1-amine, propan-2-amine, N-methylethanamine, N,N-Dimethylmethanamine. The structure of different isomers which can be drawn corresponding to the given molecular formula are given below: - Among the given isomers of ${{C}_{3}}{{H}_{9}}N$ only primary amines will liberate nitrogen gas when it will be treated with nitrous acid i.e. propan-2-amine and propan-1-amine will liberate nitrogen gas when it will be treated with nitrous acid. The reactions involved are mentioned below:\[\begin{align} & \underset{propan-1-amine}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}}+HN{{O}_{3}}\to }}\,C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH+{{N}_{2}}+HCl \\ & \underset{propan-2-amine}{\mathop{C{{H}_{3}}CH(N{{H}_{2}})C{{H}_{3}}+HN{{O}_{3}}\to }}\,C{{H}_{3}}CH(OH)C{{H}_{3}}+{{N}_{2}}+HCl \\ \end{align}\] So, the correct answer is “Option C”. Additional information:We know that there is no superimposable mirror image and there is no plane of symmetry in the molecule then the molecule is known as chiral. And the chiral carbon has four different groups attached to the carbon. This property is known as chirality and the compounds which have the same molecular formula but different compounds are said to be isomers. The compounds which are mirror images but are not identical to each other. They are known as enantiomers.Note: Structural isomers are defined as compounds which have the same molecular formula but different connectivity of atoms or bonds. The isomers which are different by the orientation of atoms in space are known as stereoisomers and the isomers which differ by their rotation around a single bond are known as conformational isomers.Recently Updated PagesMaster Class 12 Economics: Engaging Questions & Answers for SuccessMaster Class 12 Physics: Engaging Questions & Answers for SuccessMaster Class 12 English: Engaging Questions & Answers for SuccessMaster Class 12 Social Science: Engaging Questions & Answers for SuccessMaster Class 12 Maths: Engaging Questions & Answers for SuccessMaster Class 12 Business Studies: Engaging Questions & Answers for SuccessMaster Class 12 Economics: Engaging Questions & Answers for SuccessMaster Class 12 Physics: Engaging Questions & Answers for SuccessMaster Class 12 English: Engaging Questions & Answers for SuccessMaster Class 12 Social Science: Engaging Questions & Answers for SuccessMaster Class 12 Maths: Engaging Questions & Answers for SuccessMaster Class 12 Business Studies: Engaging Questions & Answers for Success

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