If F(x) = X^2 And G(x) = 2^x , Find Solution Set Of Fog(x) = Gof(x). - Toppr

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SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!QuestionSol. (i) f(x) = x-6, g(x) = x?? fog(x) = f(g(x)) = f(x) = x2 - 6 ... (1) gof(x) = g(x)) = g(x - 6) =(x - 6)2 = x2 + 36 - 12x = x2 - 12x + 36...(2) (1)+(2) .. fog(x) + gof(x) Se Open in AppSolutionVerified by TopprWas this answer helpful?0Similar QuestionsQ1f:R→R,f(x)=x2,g:R→R,g(x)=2x, then x|(fog)(x)=(gof))(x)=.........View SolutionQ2Assertion :If f(x)=sgn(x) and g(x)=x(1−x2), then fog(x) and gof(x) are continuous everywhere Reason: fog(x)=⎧⎨⎩−1,x∈(−1,0)∪(1,∞)0,x∈{−1,0,1}1,x∈(−∞,−1)∪(0,1) and gof(x)=0,∀x∈RView SolutionQ3Let f(x)=x2,g(x)=2x, then solution set of fog(x)=gof(x) isView SolutionQ4If f(x)=x2 and g(x)=2x, find solution set of fog(x)= gof(x).View SolutionQ5If f(x)=3x+24x−1 and g(x)=x+24x−3, prove that (gof)(x)=(fog)(x)=x.View Solution

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