If F(x) = X^2 And G(x) = 2^x , Find Solution Set Of Fog(x) = Gof(x). - Toppr

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SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!Standard XIIMathematicsProperties of Composite FunctionQuestionIf f(x)=x2 and g(x)=2x, find solution set of fog(x)= gof(x).Open in AppSolutionVerified by Toppr

f(x)=x2g(x)=2xf(g(x)={g(x)}2⇒f(g(x)={2x}2=22xg(f(x))=2f(x)⇒g(f(x))=2x2gof(x)=fog(x)2x2=22x⇒x2=2xx2−2x=0x(x−2)=0x=0,2

Was this answer helpful?43Similar QuestionsQ1If f(x)=x2 and g(x)=2x, find solution set of fog(x)= gof(x).View SolutionQ2Let f(x)=x2 and g(x)=2x. Then the solution of the equation fog(x)=gof(x) isView SolutionQ3f:R→R,f(x)=x2,g:R→R,g(x)=2x, then x|(fog)(x)=(gof))(x)=.........View SolutionQ4If functions f,g:R→R are defined as f(x)=x2+1,g(x)=2x−3, then find fog(x),gof(x) and gog(3)View SolutionQ5Assertion :If f(x)=sgn(x) and g(x)=x(1−x2), then fog(x) and gof(x) are continuous everywhere Reason: fog(x)=⎧⎨⎩−1,x∈(−1,0)∪(1,∞)0,x∈{−1,0,1}1,x∈(−∞,−1)∪(0,1) and gof(x)=0,∀x∈RView Solution

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