In The Above Reaction, One Mole Of Each Of Acetic Acid And Alcohol ...

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4. CH3COOH(l) + C2H5OH(l) leftharpoons CH3COOC2H5(l) + H20(l) . In the above reaction, one mole of each of acetic acid and alcohol are heated in the presence of little cone. H2SO4. On equilibrium being attained

Q. CH3​COOH(l)​+C2​H5​OH(l)​⇌CH3​COOC2​H5(l)​+H2​0(l)​ . In the above reaction, one mole of each of acetic acid and alcohol are heated in the presence of little cone. H2​SO4​. On equilibrium being attained 2984 244 Equilibrium Report Error A

1 mole of ethyl acetate is formed

17% B

2 mole of ethyl acetate are formed

33% C

1/2 moles of ethyl acetate is formed

11% D

2/3 moles of ethyl acetate is formed

39%

Solution:

In presence of little H2​SO4​ (as catalyst) about 2/3 mole of each of CH3​COOH and C2​H5​OH react to form 2/3 mole of the product at equilibrium.