In The Circuit Shown In The Figure, C1=C,C2 - - =2C,C3 - - =3C,C4

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Using the laws for series combination and parallel combination of capacitors,

1Cnet=1C+12C+1(3C+4C)

1Cnet=23/14C⇒Cnet=14C/23

Charge provided by battery =14CV/23

Therefore,

potential across C1(C)=14V/23

potential across C2(2C)=7V/23

potential across C3 and C4=2V/23

also,

PE of C1(C)=2CV2×(7/23)2

PE of C2(2C)=CV2×(7/23)2

PE of C3(3C)=6CV2/232

PE of C4(4C)=8CV2/232

Từ khóa » C1c C2=2c