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You are using an out of date browser. It may not display this or other websites correctly.You should upgrade or use an alternative browser. integration of e^(kx)
  • Thread starter finalight
  • Start date Mar 3, 2012
  • Tags ekx integration
F

finalight

Joined Sep 2011 97 Posts | 0+ Last edited by a moderator: Sep 28, 2017 i know that using the wolfham step by step calculator, integrating e^(kx) gives you e^(kx)/k but what i want to know is how do they achieve that step because i use chain rule also cannot arrive to that formula MarkFL

MarkFL

Joined Jul 2010 12K Posts | 548+ St. Augustine, FL., U.S.A.'s oldest city Last edited by a moderator: Sep 28, 2017 If you have: \int e^{kx}\,dx then you may let u=kx\:\therefore\:du=k\,dx and so you may write: \int e^{kx}\,dx=\frac{1}{k}\int e^{kx}\,k\,dx=\frac{1}{k}\int e^u\,du=\frac{1}{k}e^u+C=\frac{1}{k}e^{kx}+C Login or Register / Reply

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