Markovnikov's Rule Is Applicable To: A.) - C3H6 + HBr B. - Vedantu

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AnswerQuestion Answers for Class 12Class 12 BiologyClass 12 ChemistryClass 12 EnglishClass 12 MathsClass 12 PhysicsClass 12 Social ScienceClass 12 Business StudiesClass 12 EconomicsQuestion Answers for Class 11Class 11 EconomicsClass 11 Computer ScienceClass 11 BiologyClass 11 ChemistryClass 11 EnglishClass 11 MathsClass 11 PhysicsClass 11 Social ScienceClass 11 AccountancyClass 11 Business StudiesQuestion Answers for Class 10Class 10 ScienceClass 10 EnglishClass 10 MathsClass 10 Social ScienceClass 10 General KnowledgeQuestion Answers for Class 9Class 9 General KnowledgeClass 9 ScienceClass 9 EnglishClass 9 MathsClass 9 Social ScienceQuestion Answers for Class 8Class 8 ScienceClass 8 EnglishClass 8 MathsClass 8 Social ScienceQuestion Answers for Class 7Class 7 ScienceClass 7 EnglishClass 7 MathsClass 7 Social ScienceQuestion Answers for Class 6Class 6 ScienceClass 6 EnglishClass 6 MathsClass 6 Social ScienceQuestion Answers for Class 5Class 5 ScienceClass 5 EnglishClass 5 MathsClass 5 Social ScienceQuestion Answers for Class 4Class 4 ScienceClass 4 EnglishClass 4 MathsMarkovnikov’s rule is applicable to: a.) - C$_3$H$_6$ + HBrb.) - C$_2$H$_4$ + HClc.) - C$_3$H$_6$ + Cl$_2$d.) - C$_2$H$_4$ + HBrAnswerVerified582.6k+ viewsHint: Markovnikov’ rule is applicable to predict the regioselectivity of electrophilic addition reactions of alkenes, and alkynes. In the given options, look at the unsymmetrical alkene, or alkyne. The rule might be applied.Complete step by step solution: First, let us discuss the Markovnikov’s rule, it states that in the hydro-halogenation of unsymmetrical alkene, the hydrogen atom in the hydrogen halide like HBr, HF forms a bond with the doubly bonded carbon atom in the alkene having the greater number of hydrogen atoms. Now, look at the given options, first is C$_3$H$_6$ + HBr, propene reacting with the hydrogen bromide, propene is an unsymmetrical alkene, and HBr is an unsymmetrical reagent.So, the reaction occurred by Markovnikov’s rule is C$_3$H$_6$ + HBr $\rightarrow$ CH$_3$-CH(Br)-CH$_3$. Here, C$_3H_6$ is CH$_3$-CH=CH$_2$.Now, if we talk about C$_2$H$_4$ + HCl, and C$_2$H$_4$ + HBr there is an ethene molecule, it is a symmetrical alkene. So, Markovnikov’s rule cannot be applied.Talking about the C$_3$H$_6$ + Cl$_2$, the reaction will not happen by Markovnikov’s rule as there is absence of hydrogen halide.In the last, we can conclude that Markovnikov’s rule is applicable to C$_3$H$_6$ + HBr. As this satisfies both the condition. The correct option is (A).Note: Don’t get confused between the symmetrical, and unsymmetrical alkenes. The symmetrical alkene is an alkene in whose molecule the doubly bonded carbons bear the same ligands, whereas the unsymmetrical alkene is an alkene in whose molecule the pair of ligands on one doubly bonded carbon is different from that on the other.Recently Updated PagesMaster Class 10 General Knowledge: Engaging Questions & Answers for SuccessMaster Class 10 Science: Engaging Questions & Answers for SuccessMaster Class 10 Social Science: Engaging Questions & Answers for SuccessMaster Class 10 Maths: Engaging Questions & Answers for SuccessMaster Class 10 English: Engaging Questions & Answers for SuccessMaster Class 10 Computer Science: Engaging Questions & Answers for SuccessMaster Class 10 General Knowledge: Engaging Questions & Answers for SuccessMaster Class 10 Science: Engaging Questions & Answers for SuccessMaster Class 10 Social Science: Engaging Questions & Answers for SuccessMaster Class 10 Maths: Engaging Questions & Answers for SuccessMaster Class 10 English: Engaging Questions & Answers for SuccessMaster Class 10 Computer Science: Engaging Questions & Answers for Success

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