Mole Fraction Of C3H5(OH)3 In A Solution Of 36 G Of Water ... - Toppr

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SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!Standard XIIChemistryConcentration TermsQuestionMole fraction of C3H5(OH)3 in a solution of 36 g of water and 46 g of glycerine is:
  1. 0.46
  2. 0.36
  3. 0.2
  4. 0.4
A0.46B0.36C0.4D0.2Open in AppSolutionVerified by Toppr

C3H5(OH)3⇒C3H8O336g of H2O, 46g of glycerine.No. of moles of glycerine=4692 (where 92 is M.M. of glycerine) =0.5molesno. of moles of water=3618 (where 18 is M.M. of water) =2molesMole fraction of glycerine=MGMW+MG=0.50.5+2=0.2Hence, the correct option is C

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