NaOH + H2O2 + H2S = Na2SO4 + H2O - Chemical Equation Balancer

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Balanced Chemical Equation

2NaOH + 4H2O2 + H2S → Na2SO4 + 6H2O Reaction Info Balance Another Equation Thermodynamics Step-by-Step Solution Practice Balancing

Reaction Information Disclaimer

Word Equation

Sodium Hydroxide + Hydrogen Peroxide + Hydrogen Sulfide = Sodium Sulfate + Water

Two moles of Sodium Hydroxide [NaOH], four moles of Hydrogen Peroxide [H2O2] and one mole of Hydrogen Sulfide [H2S] react to form one mole of Sodium Sulfate [Na2SO4] and six moles of Water [H2O]

Reactants

• Sodium Hydroxide - NaOH

  White Caustic Naoh Sodium Hydrate Soda Lye Lye Caustic Soda NaOH Molar Mass NaOH Oxidation Number

• Hydrogen Peroxide - H2O2

  Peroxide Dihydrogen Dioxide Dioxidane H2O2 Molar Mass H2O2 Oxidation Number

• Hydrogen Sulfide - H2S

  Hepatic Acid Stink Damp Hepatic Gas Sour Gas Hepatate Sulfur Hydride Sulfureted Hydrogen Hydrosulfurate H2S Molar Mass H2S Oxidation Number

Products

• Sodium Sulfate - Na2SO4

  Sodium Sulphate Na2So4 Disodium Sulfate Salt Cake Disodium Sulphate Sodium Sulphate, Anhydrous Sodium Sulphate Anhydrous Sodium Sulfate, Anhydrous Na2SO4 Molar Mass Na2SO4 Oxidation Number

• Water - H2O

  Hydroxic Acid H₂O [Oh2] Aqua Pure Water Hydrogen Oxide Oxidane Dihydrogen Oxide H2O Molar Mass H2O Oxidation Number

Show Chemical Structure Image

Thermodynamics

Thermodynamics of the reaction can be calculated using a lookup table.

Choose Compound States NaOH (l)NaOH (s)NaOH H2O2 (g)H2O2 (l)H2O2 H2S (g)H2S Na2SO4 (s)Na2SO4 H2O (g)H2O (l)H2O Change States Enthalpy Calculator

Is the Reaction Exothermic or Endothermic?

NaOH (l)	2 mol	-416.89376 kJ/mol	833.78752 kJ
H2O2 (g)	4 mol	-136.10552 kJ/mol	544.42208 kJ
H2S (g)	1 mol	-20.16688 kJ/mol	20.16688 kJ
Na2SO4 (s)	1 mol	-1384.4856 kJ/mol	-1384.4856 kJ
H2O (g)	6 mol	-241.818464 kJ/mol	-1450.910784 kJ
ΣΔH°f(reactants)	-1398.37648 kJ
ΣΔH°f(products)	-2835.396384 kJ
ΔH°rxn	-1437.019904 kJ

ΣΔH°f(reactants) > ΣΔH°f(products), so NaOH + H2O2 + H2S = Na2SO4 + H2O is exothermic (releases heat). Entropy Calculator

Is the Reaction Exoentropic or Endoentropic?

ΔS = Sproducts - Sreactants. If ΔS < 0, it is exoentropic. If ΔS > 0, it is endoentropic.

NaOH (l)	2 mol	75.85592 J/(mol K)	-151.71184 J/K
H2O2 (g)	4 mol	232.88144 J/(mol K)	-931.52576 J/K
H2S (g)	1 mol	205.76912 J/(mol K)	-205.76912 J/K
Na2SO4 (s)	1 mol	149.49432 J/(mol K)	149.49432 J/K
H2O (g)	6 mol	188.715136 J/(mol K)	1132.290816 J/K
ΣΔS°(reactants)	1289.00672 J/K
ΣΔS°(products)	1281.785136 J/K
ΔS°rxn	-7.221584 J/K

ΣΔS°(reactants) > ΣΔS°(products), so NaOH + H2O2 + H2S = Na2SO4 + H2O is exoentropic (decrease in entropy). Gibbs Free Energy Calculator

Is the Reaction Exergonic or Endergonic?

ΔG = Gproducts - Greactants. If ΔG < 0, it is exergonic. If ΔG > 0, it is endergonic.

NaOH (l)	2 mol	-374.13328 kJ/mol	748.26656 kJ
H2O2 (g)	4 mol	-105.47864 kJ/mol	421.91456 kJ
H2S (g)	1 mol	-33.0536 kJ/mol	33.0536 kJ
Na2SO4 (s)	1 mol	-1266.83152 kJ/mol	-1266.83152 kJ
H2O (g)	6 mol	-228.588656 kJ/mol	-1371.531936 kJ
ΣΔG°(reactants)	-1203.23472 kJ
ΣΔG°(products)	-2638.363456 kJ
ΔG°rxn	-1435.128736 kJ

ΣΔG°(reactants) > ΣΔG°(products), so NaOH + H2O2 + H2S = Na2SO4 + H2O is exergonic (releases energy).

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [Na2SO4] [H2O]6 ) / ( [NaOH]2 [H2O2]4 [H2S] )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -1/2 * (Δ[NaOH] / Δt) = -1/4 * (Δ[H2O2] / Δt) = -(Δ[H2S] / Δt) = (Δ[Na2SO4] / Δt) = 1/6 * (Δ[H2O] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
• Ionic charges are not yet supported and will be ignored.
• Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
• Compound states [like (s) (aq) or (g)] are not required.
• You can use parenthesis () or brackets [].

How To Balance Equations

Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.

Read our article on how to balance chemical equations or ask for help in our chat.

Examples

• Sodium Hydroxide + Hydrogen Peroxide + Hydrogen Sulfide = Sodium Sulfate + Water
• Na2SO4 + H2O + Ba(NO3)2 = NaNO3 + BaSO4 + H2O9
• Na2SO4 + H2O + CO2 = Na2CO3 + H2SO4
• Na2SO4 + H2O + CaCO3 + SiO2 + Al2O3 + MgCO3 + C = Na2O*CaO*SiO2*Al2O3*MgO + CO2 + H2SO3
• Na2SO4 + H2O + Cr2O4 = Na2SO3 + Na2Cr2O7 + H2SO4
• Na2SO4 + H2O + I2 = HIO3 + Na2SO3
• Na2SO4 + H2O + KMnO4 = MnO2 + KOH + Na2SO4
• Na2SO4 + H2O + KMnO4 = Na2SO4 + MnO2 + KOH
• Na2SO4 + H2O + NH3 = Na2O + (NH4)2SO4
• C2H2 + Ag2O + NH3 = Ag2C2 + H2O + NH3
• C7H8O + NH3 = C7H9N + H2O
• C4H9OH + Br2 = C4H9Br + BrHO
• CH3CHO + H2SO4 = C2H4O2 + SO2 + H2O
• Recently Balanced Equations

Balance NaOH + H2O2 + H2S = Na2SO4 + H2O Using the Algebraic Method

To balance the equation NaOH + H2O2 + H2S = Na2SO4 + H2O using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a NaOH + b H2O2 + c H2S = d Na2SO4 + f H2O

Step 2: Create a System of Equations

Create an equation for each element (Na, O, H, S) where each term represents the number of atoms of the element in each reactant or product.

Na: 1a + 0b + 0c = 2d + 0f O: 1a + 2b + 0c = 4d + 1f H: 1a + 2b + 2c = 0d + 2f S: 0a + 0b + 1c = 1d + 0f

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination

• 1a - 2d = 0
• 1a + 2b - 4d - 1f = 0
• 1a + 2b + 2c - 2f = 0
• 1c - 1d = 0

Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 1 0 0 -2 0 0] [ 1 2 0 -4 -1 0] [ 1 2 2 0 -2 0] [ 0 0 1 -1 0 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

• a = 2 (NaOH)
• b = 4 (H2O2)
• c = 1 (H2S)
• d = 1 (Na2SO4)
• f = 6 (H2O)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

2 NaOH + 4 H2O2 + H2S = Na2SO4 + 6 H2O

Reactants	Products
Na	2	2	✔️
O	10	10	✔️
H	12	12	✔️
S	1	1	✔️

Since there is an equal number of each element in the reactants and products of 2NaOH + 4H2O2 + H2S = Na2SO4 + 6H2O, the equation is balanced.

Balance NaOH + H2O2 + H2S = Na2SO4 + H2O Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in NaOH + H2O2 + H2S = Na2SO4 + H2O must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)				Products (Right Hand Side)
Reactants	Products
NaOH	H2O2	H2S	Total	Na2SO4	H2O	Total
Na	1	1	2	2	❌
O	1	2	3	4	1	5	❌
H	1	2	2	5	2	2	❌
S	1	1	1	1	✔️

Step 2: Multiply coefficients for compounds to balance out each element

For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.

1. Na is not balanced. Add 1 molecule of NaOH to the reactant (left-hand) side to balance Sodium: 2NaOH + H2O2 + H2S = Na2SO4 + H2O

   Reactants	Products
   Na	2	2	✔️
   O	4	5	❌
   H	6	2	❌
   S	1	1	✔️

2. H is not balanced. Add 2 molecules of H2O to the product (right-hand) side to balance Hydrogen: 2NaOH + H2O2 + H2S = Na2SO4 + 3H2O

   Reactants	Products
   Na	2	2	✔️
   O	4	7	❌
   H	6	6	✔️
   S	1	1	✔️

3. O is not balanced. Add 3 molecules of H2O2 to the reactant (left-hand) side to try to balance Oxygen: 2NaOH + 4H2O2 + H2S = Na2SO4 + 3H2O

   Reactants	Products
   Na	2	2	✔️
   O	10	7	❌
   H	12	6	❌
   S	1	1	✔️

4. O is not balanced. Add 3 molecules of H2O to the product (right-hand) side to balance Oxygen: 2NaOH + 4H2O2 + H2S = Na2SO4 + 6H2O

   Reactants	Products
   Na	2	2	✔️
   O	10	10	✔️
   H	12	12	✔️
   S	1	1	✔️

Step 3: Verify that the equation is balanced

Since there are an equal number of atoms of each element on both sides, the equation is balanced.

2NaOH + 4H2O2 + H2S = Na2SO4 + 6H2O

Practice Balancing

NaOH - + + H2O2 - + + H2S - + = Na2SO4 - + + H2O - +

Reactants	Products
Na	1	2	❌
O	3	5	❌
H	5	2	❌
S	1	1	✔️

Hint: The sum of the balanced coefficients is 14. See Step-By-Step Solution

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