NH2CH2CH2NH2 Oxidation Number - ChemicalAid
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Oxidation State and Numbers of NH2CH2CH2NH2 (Ethylenediamine)
To calculate the oxidation numbers for NH2CH2CH2NH2, count the number of atoms, draw the lewis structure by adding bonds, assign electrons from each bond, and count the number of electrons assigned to each atom.
Count AtomsUse the chemical formula, NH2CH2CH2NH2, to count the number of atoms of each element.Element | Atoms |
---|---|
N | 2 |
H | 8 |
C | 2 |
Draw the lewis dot diagram for Ethylenediamine. Make sure to account for the formal and/or ionic charge of each atom.
Calculate Lewis Dot Structure for NH2CH2CH2NH2Assign ElectronsIn NH2CH2CH2NH2 there are 12 atoms sharing 11 bonds for which we need to assign the electrons in order to find the oxidation numbers. Once you have drawn the lewis diagram for NH2CH2CH2NH2, you can look at each bond and assign its electrons to the more electronegative species. Bonds in NH2CH2CH2NH2Bond | C | N | H |
---|---|---|---|
C-C | 0 | ||
C-N | 1 | -1 | |
N-H | -1 | 1 | |
N-H | -1 | 1 | |
C-H | -1 | 1 | |
C-H | -1 | 1 | |
C-N | 1 | -1 | |
N-H | -1 | 1 | |
N-H | -1 | 1 | |
C-H | -1 | 1 | |
C-H | -1 | 1 |
C | N | H | |
---|---|---|---|
Charge From Assigned Electrons | -2 | -6 | 8 |
Ionic Charge | 0 | 0 | 0 |
Total Charge | -2 | -6 | 8 |
Atoms | 2 | 2 | 8 |
Average Oxidation Number | -1 | -3 | 1 |
-3 | +1 | -2 | +1 | +0 | +1 | -3 | +1 |
N | H2 | C | H2 | C | H2 | N | H2 |
-III | I | -II | I | I | -III | I |
Ethylenediamine
What is the Oxidation State of Carbon in NH2CH2CH2NH2?
The average oxidation state of the 2 C atoms in NH2CH2CH2NH2 is -1.
What is the Oxidation State of Nitrogen in NH2CH2CH2NH2?
The average oxidation state of the 2 N atoms in NH2CH2CH2NH2 is -3.
What is the Oxidation State of Hydrogen in NH2CH2CH2NH2?
The average oxidation state of the 8 H atoms in NH2CH2CH2NH2 is +1.
Element | Oxidation Number (Avg) | Atoms | Count | Electronegativity |
---|---|---|---|---|
C | -1 | -1 (×2) | 2 | 2.6 |
N | -3 | -3 (×2) | 2 | 3.0 |
H | +1 | +1 (×8) | 8 | 2.2 |
Instructions
Enter the formula of a chemical compound to find the oxidation number of each element. A net ionic charge can be specified at the end of the compound between { and }. For example: ZnCl4{2-} or NH2NH3{+}.
Enter just an element symbol to show the common and uncommon oxidation states of the element.
- Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
- You can use parenthesis () or brackets [].
What is an oxidation state?
The oxidation state or oxidation number is an atom's charge after ionic approximation of its bonds.
How to calculate oxidation state
Read our article on finding oxidation states for a compound or use our oxidation numbers calculator to do it for you. You can also ask for help determining oxidation numbers in our chat or forums.
Examples
- No
- LiClO
- (CO3){2-}
- C2HCl3
- NiF2
- Ag2Cr2O7
- SnSO4
- Ca(H2PO4)2(H2O)
- AlOF
- HC(H)O
- (Mn)O2
- CH3CH2NCH3CH3
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