NH2CH2COOH + HNO3 = HOCH2COOH + N2 + H2O - ChemicalAid

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Balanced Chemical Equation

5NH2CH2COOH + 3HNO3 → 5HOCH2COOH + 4N2 + 4H2O Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

Reaction Information Disclaimer

Word Equation

Glycine + Nitric Acid = Glycolic Acid + Dinitrogen + Water

Five moles of Glycine [NH2CH2COOH] and three moles of Nitric Acid [HNO3] react to form five moles of Glycolic Acid [HOCH2COOH], four moles of Dinitrogen [N2] and four moles of Water [H2O]

Reactants

• Glycine - NH2CH2COOH

  Hgly H2N-Ch2-Cooh Aminoacetic Acid Glycocoll Glykokoll Aminoethanoic Acid Glycin Glyzin NH2CH2COOH Molar Mass NH2CH2COOH Oxidation Number

• Nitric Acid - HNO3

  Hono2 Hydrogen Nitrate Engravers Acid Aqua Fortis Fuming Nitric Acid Spirit Of Niter HNO3 Molar Mass HNO3 Oxidation Number

Products

• Glycolic Acid - HOCH2COOH

  Hydroxyacetic Acid Α-Hydroxyacetic Acid Alpha-Hydroxyacetic Acid Glypure 70 2-Hydroxyacetate Glycolate A-Hydroxyacetic Acid Glycollate HOCH2COOH Molar Mass HOCH2COOH Oxidation Number

• Dinitrogen - N2

  Diazyne Nitrogen Nitrogen Gas N₂ N2 Molar Mass N2 Bond Polarity N2 Oxidation Number

• Water - H2O

  Hydroxic Acid H₂O [Oh2] Aqua Pure Water Hydrogen Oxide Oxidane Dihydrogen Oxide H2O Molar Mass H2O Oxidation Number

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [HOCH2COOH]5 [N2]4 [H2O]4 ) / ( [NH2CH2COOH]5 [HNO3]3 )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -1/5 * (Δ[NH2CH2COOH] / Δt) = -1/3 * (Δ[HNO3] / Δt) = 1/5 * (Δ[HOCH2COOH] / Δt) = 1/4 * (Δ[N2] / Δt) = 1/4 * (Δ[H2O] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
• Ionic charges are not yet supported and will be ignored.
• Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
• Compound states [like (s) (aq) or (g)] are not required.
• You can use parenthesis () or brackets [].

How To Balance Equations

Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.

Read our article on how to balance chemical equations or ask for help in our chat.

Examples

• Glycine + Nitric Acid = Glycolic Acid + Dinitrogen + Water
• NH2CH2COOH + HNO3 = C2H4O3 + N2 + H2O
• NH2CH2COOH + HNO3 = C2H4O3 + N2 + H2O5
• NH2CH2COOH + HNO3 = HOCH2COOH + N2 + H2O5
• NH2CH2COOH + HNO3 = N2 + OHCH2COOH + H2O
• NH2CH2COOH + HNO3 = NH3(NO3)CH2COOH
• C2H2 + C2H5Br = CH2CHCHCH2 + HBr
• K2CO3 + CaSO4 = CaCO3 + K2O4S
• C3H4O2 + Cl2 = C3H2Cl2O2 + H2
• C2H2 + Ag2O + NH3 = Ag2C2 + H2O + NH3
• MgOHCl + NaOH = H2MgO2 + NaCl
• AgNO3 + CO2 = CAg2O3 + NO2 + O2
• MgI2 + HNO3 = Mg(NO3)2 + NO2 + HIO3 + H2O
• Recently Balanced Equations

Balance NH2CH2COOH + HNO3 = HOCH2COOH + N2 + H2O Using the Algebraic Method

To balance the equation NH2CH2COOH + HNO3 = HOCH2COOH + N2 + H2O using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a NH2CH2COOH + b HNO3 = c HOCH2COOH + d N2 + f H2O

Step 2: Create a System of Equations

Create an equation for each element (N, H, C, O) where each term represents the number of atoms of the element in each reactant or product.

N: 1a + 1b = 0c + 2d + 0f H: 5a + 1b = 4c + 0d + 2f C: 2a + 0b = 2c + 0d + 0f O: 2a + 3b = 3c + 0d + 1f

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination

• 1a + 1b - 2d = 0
• 5a + 1b - 4c - 2f = 0
• 2a - 2c = 0
• 2a + 3b - 3c - 1f = 0

Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 1 1 0 -2 0 0] [ 5 1 -4 0 -2 0] [ 2 0 -2 0 0 0] [ 2 3 -3 0 -1 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

• a = 5 (NH2CH2COOH)
• b = 3 (HNO3)
• c = 5 (HOCH2COOH)
• d = 4 (N2)
• f = 4 (H2O)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

5 NH2CH2COOH + 3 HNO3 = 5 HOCH2COOH + 4 N2 + 4 H2O

Reactants	Products
N	8	8	✔️
H	28	28	✔️
C	10	10	✔️
O	19	19	✔️

Since there is an equal number of each element in the reactants and products of 5NH2CH2COOH + 3HNO3 = 5HOCH2COOH + 4N2 + 4H2O, the equation is balanced.

Balance NH2CH2COOH + HNO3 = HOCH2COOH + N2 + H2O Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in NH2CH2COOH + HNO3 = HOCH2COOH + N2 + H2O must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)			Products (Right Hand Side)
Reactants	Products
NH2CH2COOH	HNO3	Total	HOCH2COOH	N2	H2O	Total
N	1	1	2	2	2	✔️
H	5	1	6	4	2	6	✔️
C	2	2	2	2	✔️
O	2	3	5	3	1	4	❌

Step 2: Multiply coefficients for compounds to balance out each element

For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.

1. O is not balanced. Add 1 molecule of H2O to the product (right-hand) side to balance Oxygen: NH2CH2COOH + HNO3 = HOCH2COOH + N2 + 2H2O

   Reactants	Products
   N	2	2	✔️
   H	6	8	❌
   C	2	2	✔️
   O	5	5	✔️

2. H is not balanced. Add 2 molecules of HNO3 to the reactant (left-hand) side to balance Hydrogen: NH2CH2COOH + 3HNO3 = HOCH2COOH + N2 + 2H2O

   Reactants	Products
   N	4	2	❌
   H	8	8	✔️
   C	2	2	✔️
   O	11	5	❌

3. N is not balanced. Add 1 molecule of N2 to the product (right-hand) side to balance Nitrogen: NH2CH2COOH + 3HNO3 = HOCH2COOH + 2N2 + 2H2O

   Reactants	Products
   N	4	4	✔️
   H	8	8	✔️
   C	2	2	✔️
   O	11	5	❌

4. O is not balanced. Add 2 molecules of HOCH2COOH to the product (right-hand) side to balance Oxygen: NH2CH2COOH + 3HNO3 = 3HOCH2COOH + 2N2 + 2H2O

   Reactants	Products
   N	4	4	✔️
   H	8	16	❌
   C	2	6	❌
   O	11	11	✔️

5. C is not balanced. Add 2 molecules of NH2CH2COOH to the reactant (left-hand) side to balance Carbon: 3NH2CH2COOH + 3HNO3 = 3HOCH2COOH + 2N2 + 2H2O

   Reactants	Products
   N	6	4	❌
   H	18	16	❌
   C	6	6	✔️
   O	15	11	❌

6. N is not balanced. Add 1 molecule of N2 to the product (right-hand) side to balance Nitrogen: 3NH2CH2COOH + 3HNO3 = 3HOCH2COOH + 3N2 + 2H2O

   Reactants	Products
   N	6	6	✔️
   H	18	16	❌
   C	6	6	✔️
   O	15	11	❌

7. H is not balanced. Add 1 molecule of H2O to the product (right-hand) side to balance Hydrogen: 3NH2CH2COOH + 3HNO3 = 3HOCH2COOH + 3N2 + 3H2O

   Reactants	Products
   N	6	6	✔️
   H	18	18	✔️
   C	6	6	✔️
   O	15	12	❌

8. O is not balanced. Add 1 molecule of HOCH2COOH to the product (right-hand) side to balance Oxygen: 3NH2CH2COOH + 3HNO3 = 4HOCH2COOH + 3N2 + 3H2O

   Reactants	Products
   N	6	6	✔️
   H	18	22	❌
   C	6	8	❌
   O	15	15	✔️

We could not determine all the steps needed to balance the equation using trial and error. This may mean it requires too many steps and the chemical equation is too complex to use this method, or that the equation is invalid (e.g. has 0 or non-integer coefficients). The algebraic method is likely better suited for balancing this equation.

If you would like to attempt to guess the next steps, the final element counts in the balanced equation should be:

5NH2CH2COOH + 3HNO3 = 5HOCH2COOH + 4N2 + 4H2O

Reactants	Products
N	8	8	✔️
H	28	28	✔️
C	10	10	✔️
O	19	19	✔️

Practice Balancing

NH2CH2COOH - + + HNO3 - + = HOCH2COOH - + + N2 - + + H2O - +

Reactants	Products
N	2	2	✔️
H	6	6	✔️
C	2	2	✔️
O	5	4	❌

Hint: The sum of the balanced coefficients is 21. See Step-By-Step Solution

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