NH2CH2COOH + O2 = CO2 + N2 + H2O - Chemical Equation ...

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Balanced Chemical Equation

4NH2CH2COOH + 9O2 → 8CO2 + 2N2 + 10H2O Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

Reaction Information Disclaimer

Word Equation

Glycine + Dioxygen = Carbon Dioxide + Dinitrogen + Water

NH2CH2COOH + O2 = CO2 + N2 + H2O is a Combustion reaction where four moles of Glycine [NH2CH2COOH] and nine moles of Dioxygen [O2] react to form eight moles of Carbon Dioxide [CO2], two moles of Dinitrogen [N2] and ten moles of Water [H2O]

Reaction Type

Combustion

Redox (Oxidation-Reduction) Reaction

NH2CH2COOH + O2 = CO2 + N2 + H2O might be a redox reaction.

Reactants

  • Glycine - NH2CH2COOH

    Hgly H2N-Ch2-Cooh Aminoacetic Acid Glycocoll Glykokoll Aminoethanoic Acid Glycin Glyzin NH2CH2COOH Molar Mass NH2CH2COOH Oxidation Number

  • Dioxygen - O2

    Lox Liquid Oxygen Oxygen Gas Triplet Oxygen Diatomic Oxygen Molecular Oxygen Oxygen O₂ O2 Molar Mass O2 Bond Polarity O2 Oxidation Number

Products

  • Carbon Dioxide - CO2

    Co₂ Carbon Oxide Methanedione Carbon-12 Dioxide Carbonic Acid Anhydride E290 E 290 E-290 CO2 Molar Mass CO2 Oxidation Number

  • Dinitrogen - N2

    Diazyne Nitrogen Nitrogen Gas N₂ N2 Molar Mass N2 Bond Polarity N2 Oxidation Number

  • Water - H2O

    Hydroxic Acid H₂O [Oh2] Aqua Pure Water Hydrogen Oxide Oxidane Dihydrogen Oxide H2O Molar Mass H2O Oxidation Number
Show Chemical Structure Image

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [CO2]8 [N2]2 [H2O]10 ) / ( [NH2CH2COOH]4 [O2]9 )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -1/4 * (Δ[NH2CH2COOH] / Δt) = -1/9 * (Δ[O2] / Δt) = 1/8 * (Δ[CO2] / Δt) = 1/2 * (Δ[N2] / Δt) = 1/10 * (Δ[H2O] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

  • Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
  • Ionic charges are not yet supported and will be ignored.
  • Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
  • Compound states [like (s) (aq) or (g)] are not required.
  • You can use parenthesis () or brackets [].

How To Balance Equations

Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.

Read our article on how to balance chemical equations or ask for help in our chat.

Examples

  • Glycine + Dioxygen = Carbon Dioxide + Dinitrogen + Water
  • CO2 + N2 + H2O + HCl = CH3NH3Cl + O2
  • CO2 + N2 + H2O + HCl = CH6ClN + O2
  • CO2 + N2 + H2O + O = C3H5N6O9
  • CO2 + N2 + H2O + O2 = C3H5(NO3)3
  • CO2 + N2 + H2O + O2 = C3H5N6O9
  • CO2 + N2 + H2O = (NH2)2CO + O2
  • CO2 + N2 + H2O = CH3CN + N2O
  • CO2 + N2 + H2O = HCN + O2
  • MgI2 + HNO3 = Mg(NO3)2 + NO2 + HIO3 + H2O
  • C2H2 + Ag2O + NH3 = Ag2C2 + H2O + NH3
  • C2H2 + C2H5Br = CH2CHCHCH2 + HBr
  • Fe2O3 + Br2 = Br3Fe + O2
  • Recently Balanced Equations

Balance NH2CH2COOH + O2 = CO2 + N2 + H2O Using the Algebraic Method

To balance the equation NH2CH2COOH + O2 = CO2 + N2 + H2O using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a NH2CH2COOH + b O2 = c CO2 + d N2 + f H2O

Step 2: Create a System of Equations

Create an equation for each element (N, H, C, O) where each term represents the number of atoms of the element in each reactant or product.

N: 1a + 0b = 0c + 2d + 0f H: 5a + 0b = 0c + 0d + 2f C: 2a + 0b = 1c + 0d + 0f O: 2a + 2b = 2c + 0d + 1f

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination
  • 1a - 2d = 0
  • 5a - 2f = 0
  • 2a - 1c = 0
  • 2a + 2b - 2c - 1f = 0
Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 1 0 0 -2 0 0] [ 5 0 0 0 -2 0] [ 2 0 -1 0 0 0] [ 2 2 -2 0 -1 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

  • a = 4 (NH2CH2COOH)
  • b = 9 (O2)
  • c = 8 (CO2)
  • d = 2 (N2)
  • f = 10 (H2O)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

4 NH2CH2COOH + 9 O2 = 8 CO2 + 2 N2 + 10 H2O
Reactants Products
N44✔️
H2020✔️
C88✔️
O2626✔️
Since there is an equal number of each element in the reactants and products of 4NH2CH2COOH + 9O2 = 8CO2 + 2N2 + 10H2O, the equation is balanced.

Balance NH2CH2COOH + O2 = CO2 + N2 + H2O Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in NH2CH2COOH + O2 = CO2 + N2 + H2O must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)Products (Right Hand Side)
ReactantsProducts
NH2CH2COOHO2TotalCO2N2H2OTotal
N1122❌
H5522❌
C2211❌
O224213❌

Step 2: Multiply coefficients for compounds to balance out each element

For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.

  1. N is not balanced. Add 1 molecule of NH2CH2COOH to the reactant (left-hand) side to balance Nitrogen: 2NH2CH2COOH + O2 = CO2 + N2 + H2O
    ReactantsProducts
    N22✔️
    H102❌
    C41❌
    O63❌
  2. H is not balanced. Add 4 molecules of H2O to the product (right-hand) side to balance Hydrogen: 2NH2CH2COOH + O2 = CO2 + N2 + 5H2O
    ReactantsProducts
    N22✔️
    H1010✔️
    C41❌
    O67❌
  3. C is not balanced. Add 3 molecules of CO2 to the product (right-hand) side to balance Carbon: 2NH2CH2COOH + O2 = 4CO2 + N2 + 5H2O
    ReactantsProducts
    N22✔️
    H1010✔️
    C44✔️
    O613❌
  4. O is not balanced. Add 2 molecules of NH2CH2COOH to the reactant (left-hand) side to balance Oxygen: 4NH2CH2COOH + O2 = 4CO2 + N2 + 5H2O
    ReactantsProducts
    N42❌
    H2010❌
    C84❌
    O1013❌
  5. N is not balanced. Add 1 molecule of N2 to the product (right-hand) side to balance Nitrogen: 4NH2CH2COOH + O2 = 4CO2 + 2N2 + 5H2O
    ReactantsProducts
    N44✔️
    H2010❌
    C84❌
    O1013❌
  6. H is not balanced. Add 5 molecules of H2O to the product (right-hand) side to balance Hydrogen: 4NH2CH2COOH + O2 = 4CO2 + 2N2 + 10H2O
    ReactantsProducts
    N44✔️
    H2020✔️
    C84❌
    O1018❌
  7. C is not balanced. Add 4 molecules of CO2 to the product (right-hand) side to balance Carbon: 4NH2CH2COOH + O2 = 8CO2 + 2N2 + 10H2O
    ReactantsProducts
    N44✔️
    H2020✔️
    C88✔️
    O1026❌
  8. O is not balanced. Add 8 molecules of O2 to the reactant (left-hand) side to balance Oxygen: 4NH2CH2COOH + 9O2 = 8CO2 + 2N2 + 10H2O
    ReactantsProducts
    N44✔️
    H2020✔️
    C88✔️
    O2626✔️

Step 3: Verify that the equation is balanced

Since there are an equal number of atoms of each element on both sides, the equation is balanced.

4NH2CH2COOH + 9O2 = 8CO2 + 2N2 + 10H2O

Practice Balancing

NH2CH2COOH - + + O2 - + = CO2 - + + N2 - + + H2O - +
ReactantsProducts
N12❌
H52❌
C21❌
O43❌
Hint: The sum of the balanced coefficients is 33. See Step-By-Step Solution

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