NH2SO3H + NaOH = H2O + NaNH2SO3 - Chemical Equation ...

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Balanced Chemical Equation

NH2SO3H + NaOH → H2O + NaNH2SO3 Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

Reaction Information

Word Equation

Sulfamic Acid + Sodium Hydroxide = Water + Sodium Sulfamate

NH2SO3H + NaOH = H2O + NaNH2SO3 is a Double Displacement (Metathesis) reaction where one mole of Sulfamic Acid [NH2SO3H] and one mole of Sodium Hydroxide [NaOH] react to form one mole of Water [H2O] and one mole of Sodium Sulfamate [NaNH2SO3]

Reaction Type

Double Displacement (Metathesis)

Reactants

• Sulfamic Acid - NH2SO3H

  Imidosulfonic Acid Sulphamidic Acid Sulfaminic Acid Sulphamic Acid [S(Nh2)O2(Oh)] Aminosulfonic Acid Sulfamidic Acid Amidosulfuric Acid NH2SO3H Molar Mass NH2SO3H Oxidation Number

• Sodium Hydroxide - NaOH

  White Caustic Naoh Sodium Hydrate Soda Lye Lye Caustic Soda NaOH Molar Mass NaOH Oxidation Number

Products

• Water - H2O

  Hydroxic Acid H₂O [Oh2] Aqua Pure Water Hydrogen Oxide Oxidane Dihydrogen Oxide H2O Molar Mass H2O Oxidation Number

• Sodium Sulfamate - NaNH2SO3

  Sulfamic Acid Monosodium Salt

Show Chemical Structure Image

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [H2O] [NaNH2SO3] ) / ( [NH2SO3H] [NaOH] )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -(Δ[NH2SO3H] / Δt) = -(Δ[NaOH] / Δt) = (Δ[H2O] / Δt) = (Δ[NaNH2SO3] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

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To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
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Examples

• Sulfamic Acid + Sodium Hydroxide = Water + Sodium Sulfamate
• NH2SO3H + NaOH = NH2SO3Na + H2O
• NH2SO3H + NaOH = Na2SO4 + H2O + NH3
• NH2SO3H + NaOH = Na2SO4 + NH3 + H2O
• NH2SO3H + NaOH = NaH2NSO3 + H2O
• NH2SO3H + NaOH = NaNH2SO3 + H2O
• NaOH + O2S = Na2SO3 + H2O
• PCI + O2 = PCIO
• Zn + CuSO4 = ZnSO4 + Cu3
• Ba + SO2 = Ba2(SO2)2
• NaCl + NaSO4 = NaSO4 + NaCl
• HCO3 + CaCO3 + HCl = HCO3 + CaCl + HCO3
• CaO + HNo3 = Ca(No3)2 + H2O
• Recently Balanced Equations

Balance NH2SO3H + NaOH = H2O + NaNH2SO3 Using the Algebraic Method

To balance the equation NH2SO3H + NaOH = H2O + NaNH2SO3 using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a NH2SO3H + b NaOH = c H2O + d NaNH2SO3

Step 2: Create a System of Equations

Create an equation for each element (N, H, S, O, Na) where each term represents the number of atoms of the element in each reactant or product.

N: 1a + 0b = 0c + 1d H: 3a + 1b = 2c + 2d S: 1a + 0b = 0c + 1d O: 3a + 1b = 1c + 3d Na: 0a + 1b = 0c + 1d

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination

• 1a - 1d = 0
• 3a + 1b - 2c - 2d = 0
• 1a - 1d = 0
• 3a + 1b - 1c - 3d = 0
• 1b - 1d = 0

Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 1 0 0 -1 0] [ 3 1 -2 -2 0] [ 1 0 0 -1 0] [ 3 1 -1 -3 0] [ 0 1 0 -1 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

• a = 1 (NH2SO3H)
• b = 1 (NaOH)
• c = 1 (H2O)
• d = 1 (NaNH2SO3)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

NH2SO3H + NaOH = H2O + NaNH2SO3

Reactants	Products
N	1	1	✔️
H	4	4	✔️
S	1	1	✔️
O	4	4	✔️
Na	1	1	✔️

Since there is an equal number of each element in the reactants and products of NH2SO3H + NaOH = H2O + NaNH2SO3, the equation is balanced.

Balance NH2SO3H + NaOH = H2O + NaNH2SO3 Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in NH2SO3H + NaOH = H2O + NaNH2SO3 must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)			Products (Right Hand Side)
Reactants	Products
NH2SO3H	NaOH	Total	H2O	NaNH2SO3	Total
N	1	1	1	1	✔️
H	3	1	4	2	2	4	✔️
S	1	1	1	1	✔️
O	3	1	4	1	3	4	✔️
Na	1	1	1	1	✔️

The number of atoms of each element on both sides of NH2SO3H + NaOH = H2O + NaNH2SO3 is equal which means that the equation is already balanced and no additional work is needed.

Practice Balancing

NH2SO3H - + + NaOH - + = H2O - + + NaNH2SO3 - +

Reactants	Products
N	1	1	✔️
H	4	4	✔️
S	1	1	✔️
O	4	4	✔️
Na	1	1	✔️

Hint: The sum of the balanced coefficients is 4. See Step-By-Step Solution

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