NH3 + H3PO4 = (NH4)3PO4 - Chemical Equation Balancer

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Balanced Chemical Equation

3NH3 + H3PO4 → (NH4)3PO4 Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

Reaction Information

Word Equation

Ammonia + Phosphoric Acid = Tribasic Ammonium Phosphate

NH3 + H3PO4 = (NH4)3PO4 is a Synthesis reaction where three moles of Ammonia [NH3] and one mole of Phosphoric Acid [H3PO4] combine to form one mole of Tribasic Ammonium Phosphate [(NH4)3PO4]

Reaction Type

Synthesis

Reactants

  • Ammonia - NH3

    Nitrogen Hydride Hydrogen Nitride Nh₃ Azane Nh3 NH3 Molar Mass NH3 Oxidation Number
  • Phosphoric Acid - H3PO4

    Naval Jelly E338 H3Po4 [Po(Oh)3] White Phosphoric Acid Phosphoric(V) Acid Orthophosphoric Acid H3PO4 Molar Mass H3PO4 Oxidation Number

Products

  • Tribasic Ammonium Phosphate - (NH4)3PO4

    Ammonium Phosphate (NH4)3PO4 Molar Mass (NH4)3PO4 Oxidation Number
Structure of NH3 + H3PO4 = (NH4)3PO4

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [(NH4)3PO4] ) / ( [NH3]3 [H3PO4] )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -1/3 * (Δ[NH3] / Δt) = -(Δ[H3PO4] / Δt) = (Δ[(NH4)3PO4] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

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To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

  • Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
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Examples

  • Ammonia + Phosphoric Acid = Tribasic Ammonium Phosphate
  • (NH4)3PO4 + (H3O)2SO4 = (NH4)2SO4 + (H3O)3PO4
  • (NH4)3PO4 + (NH4)2MnO4 + HNO3 = (NH4)3PO4*12MnO3 + H2O + NH4NO3
  • (NH4)3PO4 + (NH4)2MnO4 + HNO3 = (NH4)3PO4*12MnO3 + NH4NO3 + H20
  • (NH4)3PO4 + (NH4)2MoO4 + HNO3 = (NH4)3PO4*12MoO3 + NH4NO3 + H2O
  • (NH4)3PO4 + (NH4)2S = (NH4)3S + (NH4)PO4
  • (NH4)3PO4 + (NH4)6Mo7O24 + HNO3 = (NH4)3PO4*12MoO3 + NH4NO3 + H2O
  • (NH4)3PO4 + (NH4)6Mo7O24 = (NH4)3(PO4(MoO3))12 + H2O + NH3 + H2
  • (NH4)3PO4 + Ag = Ag(PO4) + NH4
  • SbCl3 + NaOH = H3SbO3 + NaCl
  • NH3*H2O + HCl = ClH4N + H2O
  • NaIO3 + H2S = NaI + S + H2O
  • HCl + Al + KIO3 = AlCl3 + KCl + I2 + H2O
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Balance NH3 + H3PO4 = (NH4)3PO4 Using the Algebraic Method

How To Balance NH3 + H3PO4 = (NH4)3PO4

To balance the equation NH3 + H3PO4 = (NH4)3PO4 using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a NH3 + b H3PO4 = c (NH4)3PO4

Step 2: Create a System of Equations

Create an equation for each element (N, H, P, O) where each term represents the number of atoms of the element in each reactant or product.

N: 1a + 0b = 3c H: 3a + 3b = 12c P: 0a + 1b = 1c O: 0a + 4b = 4c

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination
  • 1a - 3c = 0
  • 3a + 3b - 12c = 0
  • 1b - 1c = 0
  • 4b - 4c = 0
Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 1 0 -3 0] [ 3 3 -12 0] [ 0 1 -1 0] [ 0 4 -4 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

  • a = 3 (NH3)
  • b = 1 (H3PO4)
  • c = 1 ((NH4)3PO4)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

3 NH3 + H3PO4 = (NH4)3PO4
Reactants Products
N33✔️
H1212✔️
P11✔️
O44✔️
Since there is an equal number of each element in the reactants and products of 3NH3 + H3PO4 = (NH4)3PO4, the equation is balanced.

Balance NH3 + H3PO4 = (NH4)3PO4 Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in NH3 + H3PO4 = (NH4)3PO4 must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)Products (Right Hand Side)
ReactantsProducts
NH3H3PO4Total(NH4)3PO4Total
N1133
H3361212
P1111✔️
O4444✔️

Step 2: Multiply coefficients for compounds to balance out each element

For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.

  1. N is not balanced. Add 2 molecules of NH3 to the reactant (left-hand) side to balance Nitrogen: 3NH3 + H3PO4 = (NH4)3PO4
    ReactantsProducts
    N33✔️
    H1212✔️
    P11✔️
    O44✔️

Step 3: Verify that the equation is balanced

Since there are an equal number of atoms of each element on both sides, the equation is balanced.

3NH3 + H3PO4 = (NH4)3PO4

Practice Balancing

NH3 - + + H3PO4 - + = (NH4)3PO4 - +
ReactantsProducts
N13
H612
P11✔️
O44✔️
Hint: The sum of the balanced coefficients is 5. See Step-By-Step Solution

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