NH3 + H3PO4 = (NH4)3PO4 - Chemical Equation Balancer
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Balanced Chemical Equation
3NH3 + H3PO4 → (NH4)3PO4 Reaction Info Balance Another Equation Step-by-Step Solution Practice BalancingReaction Information
Word Equation
Ammonia + Phosphoric Acid = Tribasic Ammonium Phosphate
NH3 + H3PO4 = (NH4)3PO4 is a Synthesis reaction where three moles of Ammonia [NH3] and one mole of Phosphoric Acid [H3PO4] combine to form one mole of Tribasic Ammonium Phosphate [(NH4)3PO4]
Reaction Type
Synthesis
Reactants
Ammonia - NH3
Nitrogen Hydride Hydrogen Nitride Nh₃ Azane Nh3 NH3 Molar Mass NH3 Oxidation NumberPhosphoric Acid - H3PO4
Naval Jelly E338 H3Po4 [Po(Oh)3] White Phosphoric Acid Phosphoric(V) Acid Orthophosphoric Acid H3PO4 Molar Mass H3PO4 Oxidation Number
Products
Tribasic Ammonium Phosphate - (NH4)3PO4
Ammonium Phosphate (NH4)3PO4 Molar Mass (NH4)3PO4 Oxidation Number
Reaction Expressions
Equilibrium Constant & Reaction Quotient Kc or Q = ( [(NH4)3PO4] ) / ( [NH3]3 [H3PO4] )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -1/3 * (Δ[NH3] / Δt) = -(Δ[H3PO4] / Δt) = (Δ[(NH4)3PO4] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜Instructions
To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.
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Examples
- Ammonia + Phosphoric Acid = Tribasic Ammonium Phosphate
- (NH4)3PO4 + (H3O)2SO4 = (NH4)2SO4 + (H3O)3PO4
- (NH4)3PO4 + (NH4)2MnO4 + HNO3 = (NH4)3PO4*12MnO3 + H2O + NH4NO3
- (NH4)3PO4 + (NH4)2MnO4 + HNO3 = (NH4)3PO4*12MnO3 + NH4NO3 + H20
- (NH4)3PO4 + (NH4)2MoO4 + HNO3 = (NH4)3PO4*12MoO3 + NH4NO3 + H2O
- (NH4)3PO4 + (NH4)2S = (NH4)3S + (NH4)PO4
- (NH4)3PO4 + (NH4)6Mo7O24 + HNO3 = (NH4)3PO4*12MoO3 + NH4NO3 + H2O
- (NH4)3PO4 + (NH4)6Mo7O24 = (NH4)3(PO4(MoO3))12 + H2O + NH3 + H2
- (NH4)3PO4 + Ag = Ag(PO4) + NH4
- SbCl3 + NaOH = H3SbO3 + NaCl
- NH3*H2O + HCl = ClH4N + H2O
- NaIO3 + H2S = NaI + S + H2O
- HCl + Al + KIO3 = AlCl3 + KCl + I2 + H2O
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Balance NH3 + H3PO4 = (NH4)3PO4 Using the Algebraic Method
To balance the equation NH3 + H3PO4 = (NH4)3PO4 using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.
Step 1: Label Each Compound With a Variable
Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.
a NH3 + b H3PO4 = c (NH4)3PO4
Step 2: Create a System of Equations
Create an equation for each element (N, H, P, O) where each term represents the number of atoms of the element in each reactant or product.
N: 1a + 0b = 3c H: 3a + 3b = 12c P: 0a + 1b = 1c O: 0a + 4b = 4cStep 3: Solve For All Variables
Use substitution, Gaussian elimination, or a calculator to solve for each variable.
Using Substitution or Elimination- 1a - 3c = 0
- 3a + 3b - 12c = 0
- 1b - 1c = 0
- 4b - 4c = 0
Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:
[ 1 0 -3 0] [ 3 3 -12 0] [ 0 1 -1 0] [ 0 4 -4 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-StepSimplify the result to get the lowest, whole integer values.
- a = 3 (NH3)
- b = 1 (H3PO4)
- c = 1 ((NH4)3PO4)
Step 4: Substitute Coefficients and Verify Result
Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.
3 NH3 + H3PO4 = (NH4)3PO4Reactants | Products | ||
---|---|---|---|
N | 3 | 3 | ✔️ |
H | 12 | 12 | ✔️ |
P | 1 | 1 | ✔️ |
O | 4 | 4 | ✔️ |
Balance NH3 + H3PO4 = (NH4)3PO4 Using Inspection
The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in NH3 + H3PO4 = (NH4)3PO4 must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.
Step 1: Count the number of each element on the left and right hand sides
Reactants (Left Hand Side) | Products (Right Hand Side) | |||||
---|---|---|---|---|---|---|
Reactants | Products | |||||
NH3 | H3PO4 | Total | (NH4)3PO4 | Total | ||
N | 1 | 1 | 3 | 3 | ❌ | |
H | 3 | 3 | 6 | 12 | 12 | ❌ |
P | 1 | 1 | 1 | 1 | ✔️ | |
O | 4 | 4 | 4 | 4 | ✔️ |
Step 2: Multiply coefficients for compounds to balance out each element
For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.
- N is not balanced. Add 2 molecules of NH3 to the reactant (left-hand) side to balance Nitrogen: 3NH3 + H3PO4 = (NH4)3PO4
Reactants Products N 3 3 ✔️ H 12 12 ✔️ P 1 1 ✔️ O 4 4 ✔️
Step 3: Verify that the equation is balanced
Since there are an equal number of atoms of each element on both sides, the equation is balanced.
3NH3 + H3PO4 = (NH4)3PO4Practice Balancing
NH3 - + + H3PO4 - + = (NH4)3PO4 - +Reactants | Products | ||
---|---|---|---|
N | 1 | 3 | ❌ |
H | 6 | 12 | ❌ |
P | 1 | 1 | ✔️ |
O | 4 | 4 | ✔️ |
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