NH3 + NO = N2 + H2O - Chemical Equation Balancer - ChemicalAid

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Balanced Chemical Equation

4NH3 + 6NO → 5N2 + 6H2O Reaction Info Balance Another Equation Thermodynamics Step-by-Step Solution Practice Balancing

Reaction Information Disclaimer

Word Equation

Ammonia + Nitric Oxide (Radical) = Dinitrogen + Water

NH3 + NO = N2 + H2O is a Double Displacement (Metathesis) reaction where four moles of Ammonia [NH3] and six moles of Nitric Oxide (Radical) [NO] react to form five moles of Dinitrogen [N2] and six moles of Water [H2O]

Reaction Type

Double Displacement (Metathesis)

Redox (Oxidation-Reduction) Reaction

NH3 + NO = N2 + H2O might be a redox reaction.

Reactants

• Ammonia - NH3

  Nitrogen Hydride Hydrogen Nitride Nh₃ Azane Nh3 NH3 Molar Mass NH3 Oxidation Number

• Nitric Oxide (Radical) - NO

  Nitric Oxide Nitrosyl Hydride Nitrogen Protoxide Nitrogen Oxide Hydroxyamine Nitrosyl Radical Nitroxyl Nitroxide Radical NO Molar Mass NO Bond Polarity NO Oxidation Number

Products

• Dinitrogen - N2

  Diazyne Nitrogen Nitrogen Gas N₂ N2 Molar Mass N2 Bond Polarity N2 Oxidation Number

• Water - H2O

  Hydroxic Acid H₂O [Oh2] Aqua Pure Water Hydrogen Oxide Oxidane Dihydrogen Oxide H2O Molar Mass H2O Oxidation Number

Thermodynamics

Thermodynamics of the reaction can be calculated using a lookup table.

Choose Compound States NH3 (g)NH3 NO (g)NO N2 (g)N2 H2O (g)H2O (l)H2O Change States Enthalpy Calculator

Is the Reaction Exothermic or Endothermic?

NH3 (g)	4 mol	-46.10768 kJ/mol	184.43072 kJ
NO (g)	6 mol	90.24888 kJ/mol	-541.49328 kJ
N2 (g)	5 mol	0 kJ/mol	0 kJ
H2O (g)	6 mol	-241.818464 kJ/mol	-1450.910784 kJ
ΣΔH°f(reactants)	357.06256 kJ
ΣΔH°f(products)	-1450.910784 kJ
ΔH°rxn	-1807.973344 kJ

ΣΔH°f(reactants) > ΣΔH°f(products), so NH3 + NO = N2 + H2O is exothermic (releases heat). Entropy Calculator

Is the Reaction Exoentropic or Endoentropic?

ΔS = Sproducts - Sreactants. If ΔS < 0, it is exoentropic. If ΔS > 0, it is endoentropic.

NH3 (g)	4 mol	192.33848 J/(mol K)	-769.35392 J/K
NO (g)	6 mol	210.651848 J/(mol K)	-1263.911088 J/K
N2 (g)	5 mol	191.50168 J/(mol K)	957.5084 J/K
H2O (g)	6 mol	188.715136 J/(mol K)	1132.290816 J/K
ΣΔS°(reactants)	2033.265008 J/K
ΣΔS°(products)	2089.799216 J/K
ΔS°rxn	56.534208 J/K

ΣΔS°(products) > ΣΔS°(reactants), so NH3 + NO = N2 + H2O is endoentropic (increase in entropy). Gibbs Free Energy Calculator

Is the Reaction Exergonic or Endergonic?

ΔG = Gproducts - Greactants. If ΔG < 0, it is exergonic. If ΔG > 0, it is endergonic.

NH3 (g)	4 mol	-16.48496 kJ/mol	65.93984 kJ
NO (g)	6 mol	86.56696 kJ/mol	-519.40176 kJ
N2 (g)	5 mol	0 kJ/mol	0 kJ
H2O (g)	6 mol	-228.588656 kJ/mol	-1371.531936 kJ
ΣΔG°(reactants)	453.46192 kJ
ΣΔG°(products)	-1371.531936 kJ
ΔG°rxn	-1824.993856 kJ

ΣΔG°(reactants) > ΣΔG°(products), so NH3 + NO = N2 + H2O is exergonic (releases energy).

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [N2]5 [H2O]6 ) / ( [NH3]4 [NO]6 )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -1/4 * (Δ[NH3] / Δt) = -1/6 * (Δ[NO] / Δt) = 1/5 * (Δ[N2] / Δt) = 1/6 * (Δ[H2O] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
• Ionic charges are not yet supported and will be ignored.
• Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
• Compound states [like (s) (aq) or (g)] are not required.
• You can use parenthesis () or brackets [].

How To Balance Equations

Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.

Read our article on how to balance chemical equations or ask for help in our chat.

Examples

• Ammonia + Nitric Oxide (Radical) = Dinitrogen + Water
• N2 + H2O + C = CO2 + NH3
• N2 + H2O + C6H12O6 = NH3 + CO2
• N2 + H2O + CO + C = C6H2(CH3)(NO2)3
• N2 + H2O + CO + C = C7H5N3O6
• N2 + H2O + CO2 + O2 = C3H5(NO3)3
• N2 + H2O + CO2 = (CH3)2N2H2 + N2O4
• N2 + H2O + CO2 = (CH3)N2H2 + N2O4
• N2 + H2O + CO2 = C2H8N2 + N2O4
• C2HCl3O + H2O = HCl + C2H2Cl2O2
• BrCl + NaOH = NaCl + BrHO
• C6H8O7 + Na2CO3 = Na + H2O + CO2
• Li2O + MgSO4 = Li2O4S + MgO
• Recently Balanced Equations

Balance NH3 + NO = N2 + H2O Using the Algebraic Method

To balance the equation NH3 + NO = N2 + H2O using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a NH3 + b NO = c N2 + d H2O

Step 2: Create a System of Equations

Create an equation for each element (N, H, O) where each term represents the number of atoms of the element in each reactant or product.

N: 1a + 1b = 2c + 0d H: 3a + 0b = 0c + 2d O: 0a + 1b = 0c + 1d

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination

• 1a + 1b - 2c = 0
• 3a - 2d = 0
• 1b - 1d = 0

Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 1 1 -2 0 0] [ 3 0 0 -2 0] [ 0 1 0 -1 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

• a = 4 (NH3)
• b = 6 (NO)
• c = 5 (N2)
• d = 6 (H2O)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

4 NH3 + 6 NO = 5 N2 + 6 H2O

Reactants	Products
N	10	10	✔️
H	12	12	✔️
O	6	6	✔️

Since there is an equal number of each element in the reactants and products of 4NH3 + 6NO = 5N2 + 6H2O, the equation is balanced.

Balance NH3 + NO = N2 + H2O Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in NH3 + NO = N2 + H2O must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)			Products (Right Hand Side)
Reactants	Products
NH3	NO	Total	N2	H2O	Total
N	1	1	2	2	2	✔️
H	3	3	2	2	❌
O	1	1	1	1	✔️

Step 2: Multiply coefficients for compounds to balance out each element

For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.

1. H is not balanced. Add 5 molecules of H2O to the product (right-hand) side to try to balance Hydrogen: NH3 + NO = N2 + 6H2O

   Reactants	Products
   N	2	2	✔️
   H	3	12	❌
   O	1	6	❌

2. H is not balanced. Add 3 molecules of NH3 to the reactant (left-hand) side to balance Hydrogen: 4NH3 + NO = N2 + 6H2O

   Reactants	Products
   N	5	2	❌
   H	12	12	✔️
   O	1	6	❌

3. O is not balanced. Add 5 molecules of NO to the reactant (left-hand) side to balance Oxygen: 4NH3 + 6NO = N2 + 6H2O

   Reactants	Products
   N	10	2	❌
   H	12	12	✔️
   O	6	6	✔️

4. N is not balanced. Add 4 molecules of N2 to the product (right-hand) side to balance Nitrogen: 4NH3 + 6NO = 5N2 + 6H2O

   Reactants	Products
   N	10	10	✔️
   H	12	12	✔️
   O	6	6	✔️

Step 3: Verify that the equation is balanced

Since there are an equal number of atoms of each element on both sides, the equation is balanced.

4NH3 + 6NO = 5N2 + 6H2O

Practice Balancing

NH3 - + + NO - + = N2 - + + H2O - +

Reactants	Products
N	2	2	✔️
H	3	2	❌
O	1	1	✔️

Hint: The sum of the balanced coefficients is 21. See Step-By-Step Solution

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