(NH4)3(C6H5O7) (Tribasic Ammonium Citrate) Molar Mass

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Find the Molar Mass of Tribasic Ammonium Citrate, (NH4)3(C6H5O7) Step-by-Step

There are 4 easy steps to find the molar mass of (NH4)3(C6H5O7) based on its chemical formula.

1. Count The Number of Each Atom

The first step to finding the molar mass of Tribasic Ammonium Citrate is to count the number of each atom present in a single molecule using the chemical formula, (NH4)3(C6H5O7):

Element	Number of Atoms
N (Nitrogen)	3
H (Hydrogen)	17
C (Carbon)	6
O (Oxygen)	7

2. Find Atomic Mass of Each Element

Next, using the periodic table, find the atomic mass in g/mol of each element (the molar mass of an element is equal to its atomic mass):

Molar Mass (g/mol)
N (Nitrogen)	14.0067
H (Hydrogen)	1.00794
C (Carbon)	12.0107
O (Oxygen)	15.9994

3. Compute Mass of Each Element

Multiply the number of atoms by the atomic weight of each element found in steps 1 and 2 to get the mass of each element in (NH4)3(C6H5O7):

Molar Mass (g/mol)
N (Nitrogen)	3 × 14.0067 = 42.0201
H (Hydrogen)	17 × 1.00794 = 17.13498
C (Carbon)	6 × 12.0107 = 72.0642
O (Oxygen)	7 × 15.9994 = 111.9958

4. Sum Each Element's Mass

Finally, add together the total mass of each element to get the molar mass of (NH4)3(C6H5O7): 42.0201 g/mol + 17.13498 g/mol + 72.0642 g/mol + 111.9958 g/mol = 243.21508 g/mol

5. Find Mole Fraction

To find the mole fraction and percentage of each element in (NH4)3(C6H5O7), divide each total from step 3 by the total molar mass found in step 4:

Mole Fraction	Percent
N (Nitrogen)	42.0201 ÷ 243.21508 = 0.172769	× 100 = 17.2769%
H (Hydrogen)	17.13498 ÷ 243.21508 = 0.070452	× 100 = 7.0452%
C (Carbon)	72.0642 ÷ 243.21508 = 0.296298	× 100 = 29.6298%
O (Oxygen)	111.9958 ÷ 243.21508 = 0.46048	× 100 = 46.048%

Molecular Weight of (NH4)3(C6H5O7)

243.2151 g/mol

The molar mass and molecular weight of (NH4)3(C6H5O7) is 243.215. Edit Elemental Percent Composition

Convert (NH4)3(C6H5O7) From Moles to Grams

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Convert (NH4)3(C6H5O7) From Grams to Moles and Molecules

Weight g Convert to Moles

Composition of Tribasic Ammonium Citrate - (NH4)3(C6H5O7)

Element	Symbol	Atomic Mass	# of Atoms	Mass Percent
Nitrogen	N	42.0201 g/mol	3	17.2769%
Hydrogen	H	17.135 g/mol	17	7.0452%
Carbon	C	72.0642 g/mol	6	29.6298%
Oxygen	O	111.9958 g/mol	7	46.048%

Tribasic Ammonium Citrate Element Mass PercentOxygen111.996gOxygen111.996gCarbon72.0642gCarbon72.0642gNitrogen42.0201gNitrogen42.0201gHydrogen17.135gHydrogen17.135g (NH4)3(C6H5O7) # of AtomsHydrogen17Hydrogen17Oxygen7Oxygen7Carbon6Carbon6Nitrogen3Nitrogen3 🛠️ Calculate Molar Mass

Instructions

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Finding Molar Mass

Read our article on how to calculate molar mass.

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