PH Calculations Of Strong Bases

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pH Calculations of Strong Bases

pOH=-log[OH-]

Strong Bases- Strong bases are Group 1 or group 2 hydroxides. Strong bases is pretty much the same as strong acids EXCEPT you'll be calculating a pOH first, then going to the pH.

pH + pOH = 14

pH = 14- pOH

Calculate the pH of a 0.0010 M solution of NaOH.

NaOH==> Na+ + OH-

Therefore, the [OH-] equals 0.0010 M. So, to solve it, you write:

pOH = - log (0.0010) = 3.00

pH = 14.000 - 3.00 = 11.00

Calculate the pH of a 0.025 M solution of Ca(OH)2 .

Ca(OH)2 ==> Ca2+ + 2OH-

Therefore, the [OH-] equals 0.050 M. For every Ca(OH)2 you produce 2OH-.

pOH = - log (0.050) = 1.70

pH = 14.000 - 1.70 = 12.30

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