Prove That The Function F(x)=tanh^-1(x) Is An Odd Function ? | Socratic
prove that the function f(x)=tanh^-1(x) is an odd function
Calculus2 Answers
Ananda Dasgupta Apr 19, 2018The argument below can be adapted to prove that the inverse of any odd invertible function is odd.
Explanation:
The function #tanh(x) equiv (e^x-e^-x)/(e^x+e^-x)# is obviously an odd function. So
#tanh(-y) = -tanh(y)#
Writing #tanh (y) = x#, or equivalently #y = tanh^-1(x)#, this equation becomes
#tanh(-tanh^-1(x))=-x#
This implies
#-tanh^-1(x) =tanh^-1(-x)#
(where we have used #tanh^-1(tanh(x))=x#)
So, #tanh^-1(-x) = -tanh^-1(x)# - and thus #tanh(x)# is an odd function.
Answer link Yahia M. Apr 19, 2018See the explanation below
Explanation:
The logarithmic form of the function
#f(x)=# #tanh^-1x=1/2ln((1+x)/(1-x))#
Substitute each #x# by #-x#
#f(-x)=1/2ln((1-x)/(1+x))#
Using properties of logarithmic functions
#color(green) (ln(a/b)=lna-lnb)#
#=1/2(ln(1-x)-ln(1+x))#
take #-1# as a common factor
#=-1/2(ln(1+x)-ln(1-x))#
#=-1/2ln((1+x)/(1-x))=-f(x)#
#f(-x)=-f(x)#
#f(x)# is an odd function.
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