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Learn more about Labs Python divide user in put by 4 Ask Question Asked 10 years, 11 months ago Modified 10 years, 11 months ago Viewed 162 times 0

How can I divide the user input by 4?

example = input("Enter input")

so abcdefghjklmnopqrstu is 20 characters and I want to divide them by 4 so Ill have 5 characters list then I will append them all into a newlist?

I am new to python and using Python IDLE 3.3

I would like to get the total of user's input character then divided them by 4 so when I want to append them to a list it would look something like this

list = [abcde],[ghijk],[lmnop],[qrstu]

Here is my current code

user = input('ENTER TEXT: ') user.upper() print('Decrypting message: ', user) for i in range(0, len(user), 4): temp.append(user[i:i+4]) for i in range(0, len(user), 1): print(temp[i])

• python
• list
• operators
• divide

Share Improve this question Follow edited Jan 12, 2014 at 18:49 DaveDave asked Jan 12, 2014 at 18:30 DaveDaveDaveDave 30311 gold badge22 silver badges1111 bronze badges 2

• possible duplicate of split string into groups of given size – Iguananaut Commented Jan 12, 2014 at 19:05
• Really what you're asking is how to split a string into equal sized chunks. It's not really relevant that the string came from an input call. – Iguananaut Commented Jan 12, 2014 at 19:06

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2 Answers 2

Sorted by: Reset to default Highest score (default) Trending (recent votes count more) Date modified (newest first) Date created (oldest first) 7

You could use textwrap.wrap() for this:

>>> import textwrap >>> s = "abcdefghjklmnopqrstu" >>> textwrap.wrap(s, len(s)/4) ['abcde', 'fghjk', 'lmnop', 'qrstu'] Share Improve this answer Follow answered Jan 12, 2014 at 18:42 Chris SeymourChris Seymour 85.6k3232 gold badges165165 silver badges206206 bronze badges 2

• Needs to be "textwrap.wrap(s, len(s)//4)" for Python 3, which asker is using. "len(s)/4" gives floating point, which throws a TypeError when it tries to slice the string in the wrap() implementation. – CoupleWavyLines Commented Jan 12, 2014 at 19:18
• @CoupleWavyLines good point. My OS still default to 2.7, nice catch. – Chris Seymour Commented Jan 12, 2014 at 23:43

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In case you don't want to use any library, can achieve it using loop:

a = "abcdefghijklmnopqrstu" l = len(a); i = 0; r = [] while i < l and len(a) >= 4: r.append(a[:l/4]) a = a[l/4:] i += l/4 print (r) ['abcde', 'fghij', 'klmno', 'pqrst'] Share Improve this answer Follow answered Jan 12, 2014 at 19:36 ShaifaliShaifali 30933 silver badges99 bronze badges 4

• Python is not C and this has issue with edge cases: try with abcdefghijklmnopqrstuvwx – Chris Seymour Commented Jan 12, 2014 at 23:44
• @sudo_O: Yes you are correct Python is not C; Python have full-fledged library support which is it's plus point; but I thought to give this solution for newbiees as the person who is asking question(Mr.T) has mentioned that he is new to python so I just wanted to let him know all ways to solve above problem; with or without library. – Shaifali Commented Jan 13, 2014 at 15:19
• When I said Python is not C I was referring to style only... it's not very pythonic. – Chris Seymour Commented Jan 13, 2014 at 16:13
• okay; but it is python program; any ways I will keep it in mind. – Shaifali Commented Jan 15, 2014 at 14:10

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