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Python max()

The max() function returns the largest item in an iterable. It can also be used to find the largest item between two or more parameters.

Example

numbers = [9, 34, 11, -4, 27] # find the maximum number max_number = max(numbers) print(max_number) # Output: 34

The max() function has two forms:

# to find the largest item in an iterable max(iterable, *iterables, key, default) # to find the largest item between two or more objects max(arg1, arg2, *args, key)

1. max() with iterable arguments

max() Syntax

To find the largest item in an iterable, we use this syntax:

max(iterable, *iterables, key, default)

max() Parameters

• iterable - an iterable such as list, tuple, set, dictionary, etc.
• *iterables (optional) - any number of iterables; can be more than one
• key (optional) - key function where the iterables are passed and comparison is performed based on its return value
• default (optional) - default value if the given iterable is empty

max() Return Value

max() returns the largest element from an iterable.

Example 1: Get the largest item in a list

number = [3, 2, 8, 5, 10, 6] largest_number = max(number); print("The largest number is:", largest_number)

Output

The largest number is: 10

If the items in an iterable are strings, the largest item (ordered alphabetically) is returned.

Example 2: the largest string in a list

languages = ["Python", "C Programming", "Java", "JavaScript"] largest_string = max(languages); print("The largest string is:", largest_string)

Output

The largest string is: Python

In the case of dictionaries, max() returns the largest key. Let's use the key parameter so that we can find the dictionary's key having the largest value.

Example 3: max() in dictionaries

square = {2: 4, -3: 9, -1: 1, -2: 4} # the largest key key1 = max(square) print("The largest key:", key1) # 2 # the key whose value is the largest key2 = max(square, key = lambda k: square[k]) print("The key with the largest value:", key2) # -3 # getting the largest value print("The largest value:", square[key2]) # 9

Output

The largest key: 2 The key with the largest value: -3 The largest value: 9

In the second max() function, we have passed a lambda function to the key parameter.

key = lambda k: square[k]

The function returns the values of dictionaries. Based on the values (rather than the dictionary's keys), the key having the maximum value is returned.

Notes:

• If we pass an empty iterator, a ValueError exception is raised. To avoid this, we can pass the default parameter.
• If we pass more than one iterators, the largest item from the given iterators is returned.

2. max() without iterable

max() Syntax

To find the largest object between two or more parameters, we can use this syntax:

max(arg1, arg2, *args, key)

max() parameters

• arg1 - an object; can be numbers, strings, etc.
• arg2 - an object; can be numbers, strings, etc.
• *args (optional) - any number of objects
• key (optional) - key function where each argument is passed, and comparison is performed based on its return value

Basically, the max() function finds the largest item between two or more objects.

max() Return Value

max() returns the largest argument among the multiple arguments passed to it.

Example 4: Find the maximum among the given numbers

# find max among the arguments result = max(4, -5, 23, 5) print("The maximum number is:", result)

Output

The maximum number is: 23

If you need to find the smallest item, you can use the Python min() function.

Before we wrap up, let’s put your knowledge of Python max() to the test! Can you solve the following challenge?

Challenge:

Write a function to find the largest number in a list.

• For example, for inputs [1, 2, 3, 4, 5], the output should be 5.

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