Reaction Between Anisole And Concentrated HI In Excess

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Learn more about Teams Reaction between anisole and concentrated HI in excess Ask Question Asked 4 years, 7 months ago Modified 4 years, 7 months ago Viewed 3k times 2 $\begingroup$

Question:

My Attempt: In most of the ethers reaction of HI in excess yields alkane iodide products. But in case of anisole two scenarios are possible, I believe:

1. The HI breaks bond between methyl and oxygen leading to formation of phenol and methyliodide.

2. The phenol formed further reacts to form phenyliodide.

But would HI be strong enough to break partial double bond in phenol?

• organic-chemistry
• halides
• nucleophilic-substitution

Share Cite Improve this question Follow edited Apr 21, 2020 at 5:49 andselisk♦ 38.4k1414 gold badges133133 silver badges223223 bronze badges asked Apr 21, 2020 at 5:19 Aditya sureshAditya suresh 62355 silver badges1313 bronze badges $\endgroup$ 4

• $\begingroup$ Try drawing a possible mechanism: what would the first step be? $\endgroup$ – user32223 Commented Apr 21, 2020 at 6:09
• 1 $\begingroup$ Protonation of O ? $\endgroup$ – Aditya suresh Commented Apr 21, 2020 at 6:37
• 1 $\begingroup$ Correct, and then where is the easier site for I- to attack? Remember how big iodide is relative to carbon $\endgroup$ – Waylander Commented Apr 21, 2020 at 6:53
• 1 $\begingroup$ It would be easier to attack methyl group. But as we normally see in case of reaction of ethers with alkane iodides, would the product be phenol or can HI attack attack it too? Had it been dilute i wouldn't have thought that, but conc makes me think. $\endgroup$ – Aditya suresh Commented Apr 21, 2020 at 16:00

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Sorted by: Reset to default Highest score (default) Date modified (newest first) Date created (oldest first) 1 $\begingroup$

The correct answer here should be C. $\ce{I-}$ is an excellent nucleophile, it would attack the $\ce{C-O}$ bond in the methly group because phenoxide is a good leaving group as it is resonance stabilized and quite polarizable. So, the products are phenol and methyliodide. As for the excess of conc. $\ce{HI}$, it is just there so that some other nucleophile like $\ce{OH-}$ doesn't grab the limelight. I don't think it is energetically favourable to remove hydroxide from phenol to make it iodobenzene.

Share Cite Improve this answer Follow answered Apr 24, 2020 at 0:54 PhysicsaPhysicsa 5811 silver badge88 bronze badges $\endgroup$ Add a comment |

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