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theguy
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Redox Half Reaction Method
« on: February 20, 2012, 12:28:19 pm » I'm having trouble balancing a redox equation. Specifically the half reaction method.The equation is NH3 + NO2-
N2 + H2ONo matter how many times I attempt this, I can never seem to get a reasonable answer. « Last Edit: February 20, 2012, 12:57:18 pm by theguy »
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Borek
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Re: Redox Half Reaction Method
« Reply #1 on: February 20, 2012, 12:50:55 pm » If there is no negative charge between products, you won't be able to balance this equation.Are you sure it is not NH4NO2 decomposition?
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theguy
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Re: Redox Half Reaction Method
« Reply #2 on: February 20, 2012, 12:56:19 pm » Okay, I misread the equation. There is no negative charge. It was just a stray mark on my paper. Nonetheless, I've worked it without the negative and still can't get an answer that makes sense.
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Borek
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Re: Redox Half Reaction Method
« Reply #3 on: February 20, 2012, 01:22:21 pm » Not every reaction can be balanced. What you wrote is one of these cases without an answer. Compare http://www.chembuddy.com/?left=balancing-stoichiometry&right=balancing-failureAs I suggested earlier, most likely it should be NH4NO2, not NH3NO2.
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theguy
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Re: Redox Half Reaction Method
« Reply #4 on: February 20, 2012, 06:41:00 pm » Quote from: Borek on February 20, 2012, 01:22:21 pmNot every reaction can be balanced. What you wrote is one of these cases without an answer. Compare http://www.chembuddy.com/?left=balancing-stoichiometry&right=balancing-failureAs I suggested earlier, most likely it should be NH4NO2, not NH3NO2.The reactants aren't supposed to be combined. It's NH3 + NO2.
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Vidya
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Re: Redox Half Reaction Method
« Reply #5 on: February 20, 2012, 11:49:08 pm » Ok check these two balanced half reactions for the reaction given by you2NH3---> N2 + 6e- + 6H+ 8H+ + 6e- + 2NO2- --------.> N2 + 4H2O FINAL EQUATIONS IS 2NH3+ 2H+ + 2NO2- ---> 2N2 + 4H2O
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Hunter2
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Re: Redox Half Reaction Method
« Reply #6 on: February 21, 2012, 01:02:51 am » NoFINAL EQUATIONS ISNH3 + H+ + NO2- ---> N2 + 4 H2OBut above it was written there was no negative Charge on NO2So the reduction would be 2 NO2 + 8 H+ + 8 e- => N2 + 4 H2O8 NH3 => 4 N2 + 24 e- + 24 H+ 6 NO2 + 24 H+ + 24 e- => 3 N2 + 12 H2OFinal would be:8 NH3 + 6 NO2 => 7 N2 + 12 H2O
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Vidya
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Re: Redox Half Reaction Method
« Reply #7 on: February 21, 2012, 01:06:13 am » Quote from: Hunter2 on February 21, 2012, 01:02:51 amNoFINAL EQUATIONS ISNH3 + H+ + NO2- ---> N2 + 4 H2OBut above it was written there was no negative Charge on NO2So the reduction would be 2 NO2 + 8 H+ + 8 e- => N2 + 4 H2O8 NH3 => 4 N2 + 24 e- + 24 H+ 6 NO2 + 24 H+ + 24 e- => 3 N2 + 12 H2OFinal would be:8 NH3 + 6 NO2 => 7 N2 + 12 H2OI balanced this equation - NH3 + NO2- ----> N2 + H2Oin this equation NO2 has -ve charge « Last Edit: February 21, 2012, 01:45:39 am by Uma »
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Hunter2
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Re: Redox Half Reaction Method
« Reply #8 on: February 21, 2012, 02:34:21 am » In the third post it was written:QuoteOkay, I misread the equation. There is no negative charge. It was just a stray mark on my paper
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Borek
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Re: Redox Half Reaction Method
« Reply #9 on: February 21, 2012, 06:40:13 am » Quote from: Hunter2 on February 21, 2012, 01:02:51 am8 NH3 + 6 NO2 => 7 N2 + 12 H2OApparently I did something wrong before, as this is the correct answer.
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neobenzene
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Re: Redox Half Reaction Method
« Reply #10 on: March 02, 2012, 01:23:17 am » I'm not sure if I'm right, but I got8NH3 + 14NO2 + 32H+ -> 11N2 + 28H2O
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AWK
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Re: Redox Half Reaction Method
« Reply #11 on: March 02, 2012, 02:32:21 am » Quote from: neobenzene on March 02, 2012, 01:23:17 amI'm not sure if I'm right, but I got8NH3 + 14NO2 + 32H+ -> 11N2 + 28H2OCharges are unbalances
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