Reducing Fractions To Their Lowest Terms - Tiger Algebra

Step 1 :

4 Simplify — 1

Equation at the end of step 1 :

10 ((((((c2)+7c)+————)+2c)-60c)+(4•c))+15 (c2)

Step 2 :

10 Simplify —— c2

Equation at the end of step 2 :

10 ((((((c2)+7c)+——)+2c)-60c)+4c)+15 c2

Step 3 :

Rewriting the whole as an Equivalent Fraction :

3.1 Adding a fraction to a whole Rewrite the whole as a fraction using c2 as the denominator :

c2 + 7c (c2 + 7c) • c2 c2 + 7c = ——————— = —————————————— 1 c2

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Step 4 :

Pulling out like terms :

4.1 Pull out like factors : c2 + 7c = c • (c + 7)

Adding fractions that have a common denominator :

4.2 Adding up the two equivalent fractions Add the two equivalent fractions which now have a common denominatorCombine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

c • (c+7) • c2 + 10 c4 + 7c3 + 10 ——————————————————— = ————————————— c2 c2

Equation at the end of step 4 :

(c4 + 7c3 + 10) (((——————————————— + 2c) - 60c) + 4c) + 15 c2

Step 5 :

Rewriting the whole as an Equivalent Fraction :

5.1 Adding a whole to a fraction Rewrite the whole as a fraction using c2 as the denominator :

2c 2c • c2 2c = —— = ——————— 1 c2

Polynomial Roots Calculator :

5.2 Find roots (zeroes) of : F(c) = c4 + 7c3 + 10Polynomial Roots Calculator is a set of methods aimed at finding values of c for which F(c)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers c which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading CoefficientIn this case, the Leading Coefficient is 1 and the Trailing Constant is 10. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,2 ,5 ,10 Let us test ....

PQP/QF(P/Q)Divisor
-1 1 -1.00 4.00
-2 1 -2.00 -30.00
-5 1 -5.00 -240.00
-10 1 -10.00 3010.00
1 1 1.00 18.00
2 1 2.00 82.00
5 1 5.00 1510.00
10 1 10.00 17010.00

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

5.3 Adding up the two equivalent fractions

(c4+7c3+10) + 2c • c2 c4 + 9c3 + 10 ————————————————————— = ————————————— c2 c2

Equation at the end of step 5 :

(c4 + 9c3 + 10) ((——————————————— - 60c) + 4c) + 15 c2

Step 6 :

Rewriting the whole as an Equivalent Fraction :

6.1 Subtracting a whole from a fraction Rewrite the whole as a fraction using c2 as the denominator :

60c 60c • c2 60c = ——— = ———————— 1 c2

Polynomial Roots Calculator :

6.2 Find roots (zeroes) of : F(c) = c4 + 9c3 + 10 See theory in step 5.2 In this case, the Leading Coefficient is 1 and the Trailing Constant is 10. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,2 ,5 ,10 Let us test ....

PQP/QF(P/Q)Divisor
-1 1 -1.00 2.00
-2 1 -2.00 -46.00
-5 1 -5.00 -490.00
-10 1 -10.00 1010.00
1 1 1.00 20.00
2 1 2.00 98.00
5 1 5.00 1760.00
10 1 10.00 19010.00

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

6.3 Adding up the two equivalent fractions

(c4+9c3+10) - (60c • c2) c4 - 51c3 + 10 ———————————————————————— = —————————————— c2 c2

Equation at the end of step 6 :

(c4 - 51c3 + 10) (———————————————— + 4c) + 15 c2

Step 7 :

Rewriting the whole as an Equivalent Fraction :

7.1 Adding a whole to a fraction Rewrite the whole as a fraction using c2 as the denominator :

4c 4c • c2 4c = —— = ——————— 1 c2

Polynomial Roots Calculator :

7.2 Find roots (zeroes) of : F(c) = c4 - 51c3 + 10 See theory in step 5.2 In this case, the Leading Coefficient is 1 and the Trailing Constant is 10. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,2 ,5 ,10 Let us test ....

PQP/QF(P/Q)Divisor
-1 1 -1.00 62.00
-2 1 -2.00 434.00
-5 1 -5.00 7010.00
-10 1 -10.00 61010.00
1 1 1.00 -40.00
2 1 2.00 -382.00
5 1 5.00 -5740.00
10 1 10.00 -40990.00

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

7.3 Adding up the two equivalent fractions

(c4-51c3+10) + 4c • c2 c4 - 47c3 + 10 —————————————————————— = —————————————— c2 c2

Equation at the end of step 7 :

(c4 - 47c3 + 10) ———————————————— + 15 c2

Step 8 :

Rewriting the whole as an Equivalent Fraction :

8.1 Adding a whole to a fraction Rewrite the whole as a fraction using c2 as the denominator :

15 15 • c2 15 = —— = ——————— 1 c2

Polynomial Roots Calculator :

8.2 Find roots (zeroes) of : F(c) = c4 - 47c3 + 10 See theory in step 5.2 In this case, the Leading Coefficient is 1 and the Trailing Constant is 10. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,2 ,5 ,10 Let us test ....

PQP/QF(P/Q)Divisor
-1 1 -1.00 58.00
-2 1 -2.00 402.00
-5 1 -5.00 6510.00
-10 1 -10.00 57010.00
1 1 1.00 -36.00
2 1 2.00 -350.00
5 1 5.00 -5240.00
10 1 10.00 -36990.00

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

8.3 Adding up the two equivalent fractions

(c4-47c3+10) + 15 • c2 c4 - 47c3 + 15c2 + 10 —————————————————————— = ————————————————————— c2 c2

Checking for a perfect cube :

8.4 c4 - 47c3 + 15c2 + 10 is not a perfect cube

Trying to factor by pulling out :

8.5 Factoring: c4 - 47c3 + 15c2 + 10 Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: 15c2 + 10 Group 2: c4 - 47c3 Pull out from each group separately :Group 1: (3c2 + 2) • (5)Group 2: (c - 47) • (c3)Bad news !! Factoring by pulling out fails : The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

8.6 Find roots (zeroes) of : F(c) = c4 - 47c3 + 15c2 + 10 See theory in step 5.2 In this case, the Leading Coefficient is 1 and the Trailing Constant is 10. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,2 ,5 ,10 Let us test ....

PQP/QF(P/Q)Divisor
-1 1 -1.00 73.00
-2 1 -2.00 462.00
-5 1 -5.00 6885.00
-10 1 -10.00 58510.00
1 1 1.00 -21.00
2 1 2.00 -290.00
5 1 5.00 -4865.00
10 1 10.00 -35490.00

Polynomial Roots Calculator found no rational roots

Final result :

c4 - 47c3 + 15c2 + 10 ————————————————————— c2

Từ khóa » C2+7c+10/c2+2c-15•4c+12/3c+15