Reducing Fractions To Their Lowest Terms - Tiger Algebra
Step 1 :
Equation at the end of step 1 :
x 9 (((3•(x2))+(9•————))-9)•((((2•(x2))-9x)+(—•(x3)))-3x2) (x2) 2Step 2 :
9 Simplify — 2Equation at the end of step 2 :
x 9 (((3•(x2))+(9•————))-9)•((((2•(x2))-9x)+(—•x3))-3x2) (x2) 2Step 3 :
Equation at the end of step 3 :
x 9x3 (((3•(x2))+(9•————))-9)•((((2•(x2))-9x)+———)-3x2) (x2) 2Step 4 :
Equation at the end of step 4 :
x 9x3 (((3•(x2))+(9•————))-9)•(((2x2-9x)+———)-3x2) (x2) 2Step 5 :
Rewriting the whole as an Equivalent Fraction :
5.1 Adding a fraction to a whole Rewrite the whole as a fraction using 2 as the denominator :
2x2 - 9x (2x2 - 9x) • 2 2x2 - 9x = ———————— = —————————————— 1 2Equivalent fraction : The fraction thus generated looks different but has the same value as the whole Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Step 6 :
Pulling out like terms :
6.1 Pull out like factors : 2x2 - 9x = x • (2x - 9)
Adding fractions that have a common denominator :
6.2 Adding up the two equivalent fractions Add the two equivalent fractions which now have a common denominatorCombine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
x • (2x-9) • 2 + 9x3 9x3 + 4x2 - 18x ———————————————————— = ——————————————— 2 2Equation at the end of step 6 :
x (9x3+4x2-18x) (((3•(x2))+(9•————))-9)•(—————————————-3x2) (x2) 2Step 7 :
Rewriting the whole as an Equivalent Fraction :
7.1 Subtracting a whole from a fraction Rewrite the whole as a fraction using 2 as the denominator :
3x2 3x2 • 2 3x2 = ——— = ——————— 1 2Step 8 :
Pulling out like terms :
8.1 Pull out like factors : 9x3 + 4x2 - 18x = x • (9x2 + 4x - 18)
Trying to factor by splitting the middle term
8.2 Factoring 9x2 + 4x - 18 The first term is, 9x2 its coefficient is 9 .The middle term is, +4x its coefficient is 4 .The last term, "the constant", is -18 Step-1 : Multiply the coefficient of the first term by the constant 9 • -18 = -162 Step-2 : Find two factors of -162 whose sum equals the coefficient of the middle term, which is 4 .
| -162 | + | 1 | = | -161 |
| -81 | + | 2 | = | -79 |
| -54 | + | 3 | = | -51 |
| -27 | + | 6 | = | -21 |
| -18 | + | 9 | = | -9 |
| -9 | + | 18 | = | 9 |
| -6 | + | 27 | = | 21 |
| -3 | + | 54 | = | 51 |
| -2 | + | 81 | = | 79 |
| -1 | + | 162 | = | 161 |
Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored
Adding fractions that have a common denominator :
8.3 Adding up the two equivalent fractions
x • (9x2+4x-18) - (3x2 • 2) 9x3 - 2x2 - 18x ——————————————————————————— = ——————————————— 2 2Equation at the end of step 8 :
x (9x3-2x2-18x) (((3•(x2))+(9•————))-9)•————————————— (x2) 2Step 9 :
x Simplify —— x2Dividing exponential expressions :
9.1 x1 divided by x2 = x(1 - 2) = x(-1) = 1/x1 = 1/x
Equation at the end of step 9 :
1 (9x3-2x2-18x) (((3•(x2))+(9•—))-9)•————————————— x 2Step 10 :
Equation at the end of step 10 :
9 (9x3 - 2x2 - 18x) ((3x2 + —) - 9) • ————————————————— x 2Step 11 :
Rewriting the whole as an Equivalent Fraction :
11.1 Adding a fraction to a whole Rewrite the whole as a fraction using x as the denominator :
3x2 3x2 • x 3x2 = ——— = ——————— 1 xAdding fractions that have a common denominator :
11.2 Adding up the two equivalent fractions
3x2 • x + 9 3x3 + 9 ——————————— = ——————— x xEquation at the end of step 11 :
(3x3 + 9) (9x3 - 2x2 - 18x) (————————— - 9) • ————————————————— x 2Step 12 :
Rewriting the whole as an Equivalent Fraction :
12.1 Subtracting a whole from a fraction Rewrite the whole as a fraction using x as the denominator :
9 9 • x 9 = — = ————— 1 xStep 13 :
Pulling out like terms :
13.1 Pull out like factors : 3x3 + 9 = 3 • (x3 + 3)
Trying to factor as a Sum of Cubes :
13.2 Factoring: x3 + 3 Theory : A sum of two perfect cubes, a3 + b3 can be factored into : (a+b) • (a2-ab+b2)Proof : (a+b) • (a2-ab+b2) = a3-a2b+ab2+ba2-b2a+b3 = a3+(a2b-ba2)+(ab2-b2a)+b3= a3+0+0+b3= a3+b3Check : 3 is not a cube !! Ruling : Binomial can not be factored as the difference of two perfect cubes
Polynomial Roots Calculator :
13.3 Find roots (zeroes) of : F(x) = x3 + 3Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading CoefficientIn this case, the Leading Coefficient is 1 and the Trailing Constant is 3. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,3 Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | 2.00 | |
| -3 | 1 | -3.00 | -24.00 | |
| 1 | 1 | 1.00 | 4.00 | |
| 3 | 1 | 3.00 | 30.00 |
Polynomial Roots Calculator found no rational roots
Adding fractions that have a common denominator :
13.4 Adding up the two equivalent fractions
3 • (x3+3) - (9 • x) 3x3 - 9x + 9 ———————————————————— = ———————————— x xEquation at the end of step 13 :
(3x3 - 9x + 9) (9x3 - 2x2 - 18x) —————————————— • ————————————————— x 2Step 14 :
Step 15 :
Pulling out like terms :
15.1 Pull out like factors : 3x3 - 9x + 9 = 3 • (x3 - 3x + 3)
Step 16 :
Pulling out like terms :
16.1 Pull out like factors : (9x3 - 2x2 - 18x) = x • (9x2 - 2x - 18)
Polynomial Roots Calculator :
16.2 Find roots (zeroes) of : F(x) = x3 - 3x + 3 See theory in step 13.3 In this case, the Leading Coefficient is 1 and the Trailing Constant is 3. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,3 Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | 5.00 | |
| -3 | 1 | -3.00 | -15.00 | |
| 1 | 1 | 1.00 | 1.00 | |
| 3 | 1 | 3.00 | 21.00 |
Polynomial Roots Calculator found no rational roots
Trying to factor by splitting the middle term
16.3 Factoring 9x2 - 2x - 18 The first term is, 9x2 its coefficient is 9 .The middle term is, -2x its coefficient is -2 .The last term, "the constant", is -18 Step-1 : Multiply the coefficient of the first term by the constant 9 • -18 = -162 Step-2 : Find two factors of -162 whose sum equals the coefficient of the middle term, which is -2 .
| -162 | + | 1 | = | -161 |
| -81 | + | 2 | = | -79 |
| -54 | + | 3 | = | -51 |
| -27 | + | 6 | = | -21 |
| -18 | + | 9 | = | -9 |
| -9 | + | 18 | = | 9 |
| -6 | + | 27 | = | 21 |
| -3 | + | 54 | = | 51 |
| -2 | + | 81 | = | 79 |
| -1 | + | 162 | = | 161 |
Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored
Final result :
3 • (x3 - 3x + 3) • (9x2 - 2x - 18) ——————————————————————————————————— 2Từ khóa » G(x)=f(3x+1)+9x^3+9/2x^2
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